C copynpaste New Member Joined Mar 4, 2013 Messages 22 Gender Undisclosed HSC 2014 May 19, 2013 #1 http://community.boredofstudies.org/attachment.php?attachmentid=28127&d=1368959745 Need help with (b) and (c)
http://community.boredofstudies.org/attachment.php?attachmentid=28127&d=1368959745 Need help with (b) and (c)
B braintic Well-Known Member Joined Jan 20, 2011 Messages 2,137 Gender Undisclosed HSC N/A May 19, 2013 #2 copynpaste said: View attachment 28127 http://community.boredofstudies.org/attachment.php?attachmentid=28127&d=1368959745 Need help with (b) and (c) Click to expand... (b) AD^2 + AG^2 = DG^2 = BG^2 AD^2 + AG^2 = BG^2 (corresponding sides of congruent rectangles) AD^2 + AG^2 = (AB-AG)^2 (Since BG=AB-AG) AD^2 + AG^2 = AB^2 + AG^2 - 2AB.AG AD^2 = AB^2 - 2AB.AG Rearrange to get the result, sub in to get the answer. part (c) is easy after doing (b) - just a rectangle minus 2 triangles Last edited: May 19, 2013
copynpaste said: View attachment 28127 http://community.boredofstudies.org/attachment.php?attachmentid=28127&d=1368959745 Need help with (b) and (c) Click to expand... (b) AD^2 + AG^2 = DG^2 = BG^2 AD^2 + AG^2 = BG^2 (corresponding sides of congruent rectangles) AD^2 + AG^2 = (AB-AG)^2 (Since BG=AB-AG) AD^2 + AG^2 = AB^2 + AG^2 - 2AB.AG AD^2 = AB^2 - 2AB.AG Rearrange to get the result, sub in to get the answer. part (c) is easy after doing (b) - just a rectangle minus 2 triangles
C copynpaste New Member Joined Mar 4, 2013 Messages 22 Gender Undisclosed HSC 2014 May 19, 2013 #3 Thanks so much!