Q3
Let the 2 circles intersect at A & B, with A on the line PQ, and B on RS
Let angle APR = @
.: angle PRB = 180 - @ ( APR & PRB are co-interior angles and PQ//RS)
.: angle PAB = @ (ABRP is cyclic quad, PRB + PAB = 180)
.: angle QSB = angle PAB = @ (ABSQ a cyclic quad; ext angle of a cyclic quad = interior opp angle)
.: angle PRS + angle QSR = 180 (i.e. the 2 angles are supplementary)
But PRS & QSR are co-interior angles
.: PR//QS
.: PQSR is a paralellogram (opp sides are parallel)
.: PQ = RS (opp sides of //gram)
QED