Annoyingly hard q (1 Viewer)

darlking

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Please help me with this, i dont even know where to start.
 

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Trebla

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When solving for the points of intersection



and



We have



Since the circle is tangent symmetrically the two points of contact must have the same y-value. Hence there is only one solution in y to the equation above. If there is only one solution the discriminant must be zero.



When you actually solve the equation for y using the quadratic formula and the result in (i) you get



However, from the diagram it is pretty obvious thay y must be positive so

 

Makematics

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you couldnt find any solutions to a 2012 hsc paper? :S check out itute or something next time lol
 

Trebla

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There are actually sample solutions on the Board of Studies website for recent years if you haven't noticed.
 

darlking

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I didn't pay attention to that information.

@Makematics
 

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