The Helping Me in Geometry Thread (1 Viewer)

[Menomaths]

I suck at Geometry

 

[HSC2014]

Not sure if serious (sorry) but diagonals in rectangle are equal and bisect each other.

 

[Menomaths]

I am serious... Nearly first time doing Geometry. I don't know how to find theta

 

[Squar3root]

X=5 cm (because, diagonals that bisect each other are equal)

Hence, the triangle is isosceles (because, same reason as above) so theta = (180-48)/2 = 66 degrees

 

[Menomaths]

Wow... I feel stupid now... THANKS THOUGH

 

[HSC2014]

1 day later still not sure if serious LOL

 

[Solution]

1 day later still not sure if serious LOL

Oh come off it.

He'll improve

 

[obliviousninja]

Wow... I feel stupid now... THANKS THOUGH

...its all part of your snake strat. get other people to utilize their time answering your questions.

 

[Menomaths]

Drawing the parallelogram probably took longer than answering the question lol

 

[Squar3root]

Drawing the parallelogram probably took longer than answering the question lol

LOL Definitely

 

[Menomaths]

 

[HeroicPandas]

U know that this is a parallelogram because opposite sides are parallel and opposite sides are equal in length

Area of parallelogram = base x perpendicular height

http://www.google.com.au/imgres?um=...bnh=164&tbnw=301&start=0&ndsp=15&tx=174&ty=74

Btw, the perpendicular height should be drawn from B or D

 

[Menomaths]

AHHHHHH right! I got all the plane geometry questions before this part right, then as soon as pure Geometry comes in...

 

[HeroicPandas]

AHHHHHH right! I got all the plane geometry questions before this part right, then as soon as pure Geometry comes in...

U still have time to improve!

 

[Menomaths]

U still have time to improve!

Yep

 

[Menomaths]

In the answer they first calculated the area of the triangle by 1/2bh by using 12 and 16. Shouldn't QS be used as the 'h'?

 

[HeroicPandas]

Look at the TWO BIG right-angled triangles

Areas areas are the same,







12 x 16 = QR x PR

QR = 192/PR

Find PR using the glorious Pythagoras theorem

 

[HeroicPandas]

Btw please do not look at the answer, it will stuff up ur thinking patterns

If u cannot answer a question, try harder and make an AIM to work towards

 

[Menomaths]

Look at the TWO BIG right-angled triangles

Areas areas are the same,







12 x 16 = QR x PR

QR = 192/PR

Find PR using the glorious Pythagoras theorem

How can they be the same!?

 

[HeroicPandas]

How can they be the same!?

They are the same triangle, look carefully, the 2 right-angled triangles are the SAME

Well u can obviously see one triangle is PQR (with right angle on Q)

The other triangle is QPR with right angle at S