HSC 2013 Maths Marathon (archive) (7 Viewers)

leesh95 · Oct 20, 2013

Re: HSC 2013 2U Marathon

Menomaths said:

a)67
b)430

Badsiii · Oct 20, 2013

Re: HSC 2013 2U Marathon

Menomaths said:
second one's incorrect

Sorry I read it as twelve not twenty
T10= 39 t20=79
S= 11/2(39+79)=649

Menomaths · Oct 20, 2013

Re: HSC 2013 2U Marathon

Still incorrect

Menomaths · Oct 20, 2013

Re: HSC 2013 2U Marathon

leesh95 said:
a)67
b)430

second one's incorrect

best troll question evar :'D

leesh95 · Oct 20, 2013

Re: HSC 2013 2U Marathon

Badsiii said:
Sorry I read it as twelve not twenty
T10= 39 t20=79
S= 10/2(39+79)=590

I think I get it 11/2 (79+39)
=649

Badsiii · Oct 20, 2013

Re: HSC 2013 2U Marathon

Menomaths said:
Still incorrect

It's correct now

Menomaths · Oct 20, 2013

Re: HSC 2013 2U Marathon

Badsiii said:
Sorry I read it as twelve not twenty
T10= 39 t20=79
S= 11/2(39+79)=649

Yeah, that's right now

Youi_ · Oct 20, 2013

Re: HSC 2013 2U Marathon

$A function f(x) is defined by f(x)= 1+2cos(x)$

$$ Find the area under the curve f(x) between$

$x = \frac{-\pi}{2} \ $and$ \ \frac{2\pi}{3}$

Menomaths · Oct 20, 2013

Re: HSC 2013 2U Marathon

Youi_ said:
$A function f(x) is defined by f(x)= 1+2cos(x)$

$$ Find the area under the curve f(x) between$

$x = \frac{-\pi}{2} \ $and$ \ \frac{2\pi}{3}$

7.397

Youi_ · Oct 20, 2013

Re: HSC 2013 2U Marathon

Menomaths said:
7.397

.... funny

Menomaths · Oct 20, 2013

Re: HSC 2013 2U Marathon

Do you want it in exact form?

HeroicPandas · Oct 20, 2013

Re: HSC 2013 2U Marathon

Youi_ said:
.... funny

because its not in exact form?

Youi_ · Oct 20, 2013

Re: HSC 2013 2U Marathon

HeroicPandas said:
because its not in exact form?

because there is no working out he just looked at solutions and meh

Menomaths · Oct 20, 2013

Re: HSC 2013 2U Marathon

Youi_ said:
because there is no working out he just looked at solutions and meh

ugh..no

Youi_ · Oct 20, 2013

Re: HSC 2013 2U Marathon

Menomaths said:
ugh..no

Nevermind I sound like an old grumpy lady

Menomaths · Oct 20, 2013

Re: HSC 2013 2U Marathon

Youi_ said:
Nevermind I sound like an old grumpy lady

yup

mahmoudali · Oct 20, 2013

Re: HSC 2013 2U Marathon

Menomaths said:
yup

he's a true moeeeeeyyyyyy

mahmoudali · Oct 20, 2013

Re: HSC 2013 2U Marathon

mahmoudali said:
he's a true moeeeeeyyyyyy

post a question sy

Menomaths · Oct 20, 2013

Re: HSC 2013 2U Marathon

mahmoudali said:
he's a true moeeeeeyyyyyy

haha

Sy123 · Oct 20, 2013

Re: HSC 2013 2U Marathon

$$Let$ \ \ y=uv \ \ $where$ \ \ u,v \ \ $are functions of$ \ \ x$

$$i) Find an expression for$ \ \ y'', y''', y''''$

$$ii) Expand$ \ \ (1+x)^2, \ (1+x)^3, \ (1+x)^4$

$iii) Notice the pattern and hence find$

$\frac{d^5}{dx^5}(e^{-x} (1+x^2))$

HSC 2013 Maths Marathon (archive) (7 Viewers)

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