HSC 2014 MX2 Marathon (archive) (4 Viewers)

[Davo_01]

Re: HSC 2014 4U Marathon

Yes I guess but yes I should have showed that by dividing by 2. I will do that next time. Hahaha next one when you have time please.

Have a look at some of the questions I posted earlier in the advance thread

 

[hit patel]

Re: HSC 2014 4U Marathon

Have a look at some of the questions I posted earlier in the advance thread

Ok but I dont think that thread is for me at all. Its for guys like sy123 and you.

 

[hit patel]

Re: HSC 2014 4U Marathon

BTW Carrotsticks or anyone please notify me as to when you are holding the mx2 trial like you did last time or whether you are holding it.... Thanks

 

[Carrotsticks]

Re: HSC 2014 4U Marathon

It will be hosted around October.

 

[hit patel]

Re: HSC 2014 4U Marathon

It will be hosted around October.

Thanks. And any year 12 can participate that does 4u? or are there certain restrictions?

 

[Carrotsticks]

Re: HSC 2014 4U Marathon

The only restriction is that you must be in high school, but the target audience are those who feel that they are competent with the fundamentals and seek a considerably more difficult paper to attempt.

We've had Year 11's attempt the Extension 2 BOS Trials before.

 

[Ikki]

Re: HSC 2014 4U Marathon

Haha should be fun, altho I've heard some people became demoralised after getting like an 'super asian fail' Under 80% whilst that was an amazing mark for the exam.
Where's this held, library near the station?

 

[Sy123]

Re: HSC 2014 4U Marathon

Haha should be fun, altho I've heard some people became demoralised after getting like an 'super asian fail' Under 80% whilst that was an amazing mark for the exam.
Where's this held, library near the station?

First place got ~67 iirc and came first in the state, and second place got one mark below and came 7th

 

[Ikki]

Re: HSC 2014 4U Marathon

FAAAAAAAAAAAAAAAAAAAAAAAR That is so crazy.
Two comments:
1. Bro where does carrot get these qs.
2. Well i'm thinking most people got under 50 (average under 50?) lol. Could be demoralising... Actual fail.

 

[Sy123]

Re: HSC 2014 4U Marathon

FAAAAAAAAAAAAAAAAAAAAAAAR That is so crazy.
Two comments:
1. Bro where does carrot get these qs.
2. Well i'm thinking most people got under 50 (average under 50?) lol. Could be demoralising... Actual fail.

1. His brain

2. Well below 50s lol

 

[Sy123]

Re: HSC 2014 4U Marathon

 

[dunjaaa]

Re: HSC 2014 4U Marathon

By inspection x=6 ->4! = 24

 

[braintic]

Re: HSC 2014 4U Marathon

By inspection x=6 ->4! = 24

x=1 is almost as obvious

 

[mreditor16]

Re: HSC 2014 4U Marathon

Three pirates are sharing out the contents of a treasure chest containing forty-eight
gold coins and two lead coins. The first pirate takes out coins one at a time until a lead
coin is taken. The second pirate then takes out coins one at a time until the second lead
coin is taken. The third pirate then takes all of the remaining coins.
(i) In how many ways can the coins be distributed? (1 mark)
(ii) What is the probability that all three pirates receive some gold coins? (2 mark)


I'll post the provided solution after some-one gets it.

 

[Kurosaki]

Re: HSC 2014 4U Marathon

Three pirates are sharing out the contents of a treasure chest containing forty-eight
gold coins and two lead coins. The first pirate takes out coins one at a time until a lead
coin is taken. The second pirate then takes out coins one at a time until the second lead
coin is taken. The third pirate then takes all of the remaining coins.
(i) In how many ways can the coins be distributed? (1 mark)
(ii) What is the probability that all three pirates receive some gold coins? (2 mark)


I'll post the provided solution after some-one gets it.

I. 2450
Ii 2447/2450?

 

[mreditor16]

Re: HSC 2014 4U Marathon

sorry, kurosaki, that is incorrect.

 

[awesome-0_4000]

Re: HSC 2014 4U Marathon

i) 48!
ii) 47!/48!=1/48

 

[mreditor16]

Re: HSC 2014 4U Marathon

sorry, awesome, that is incorrect. keep on trying, guys!

 

[iStudent]

Re: HSC 2014 4U Marathon

Three pirates are sharing out the contents of a treasure chest containing forty-eight
gold coins and two lead coins. The first pirate takes out coins one at a time until a lead
coin is taken. The second pirate then takes out coins one at a time until the second lead
coin is taken. The third pirate then takes all of the remaining coins.
(i) In how many ways can the coins be distributed? (1 mark)
(ii) What is the probability that all three pirates receive some gold coins? (2 mark)


I'll post the provided solution after some-one gets it.

Is (i) 2C1*48C3 = 34592?

 

[Kurosaki]

Re: HSC 2014 4U Marathon

(I) 1225