Ekman
Well-Known Member
- Joined
- Oct 23, 2014
- Messages
- 1,615
- Gender
- Male
- HSC
- 2015
Re: HSC 2015 4U Marathon
In a geometrical sense, I drew up z+2 and z-2, and their intersection point. Thus utilizing the given formula I was able to prove that points z+2, z-2 and the intersection point are points on an isosceles triangle. Since z+2 and z-2 are equidistant from the origin the point of intersection is on the imaginary axis, thus as z varies, the point of intersection will have the locus of the imaginary axis, as long as it satisfies the formula given.In hsc, they dont expect you to algebraically prove this locus type q.
this is one of those geometrical locus