HSC Question Trigonometric Functions (1 Viewer)

BlueGas · May 28, 2015

I need help with question iii) and iv) thanks!

InteGrand · May 28, 2015

BlueGas said:
I need help with question iii) and iv) thanks!

$(iii) Based on our answers to (i) and (ii), we can see that the required solutions are $x=-\frac{\pi}{3},0,\frac{\pi}{3}$.$

$(iv) Based on our answer to (iii), we can see that the solution to the inequality is $-\frac{\pi}{3}\leq x\leq 0$ or $\frac{\pi}{3}\leq x\leq \frac{\pi}{2}$ (i.e. these are the intervals where the graph of $\sin x$ is on or below that of $\frac{1}{2}\tan x$).$

HSC Question Trigonometric Functions (1 Viewer)

BlueGas

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InteGrand

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