Physics question on centripetal force (1 Viewer)

InteGrand · Jul 24, 2015

zenia99 said:
View attachment 32233

$The mass $M$ has its weight force provide the centripetal force, so the centripetal force has magnitude $F_c = Mg=0.2\text{ kg}\times 9.8\text{ m s}^{-2}=1.96\text{ N}$. Since $F_c = \frac{mv^2}{r}$, we have$

$m=\frac{rF_c}{v^2}$, where $r=0.6\text{ m}$, $v=8.37\text{ m s}^{-1}$, $F_c = 1.96\text{ N}$

$=\frac{0.6\text{ m}\times 1.96\text{ N}}{(8.37\text{ m s}^{-1})^2}$

$=0.016786...\text{ kg}$

$$\approx 17\text{ g } (2\text{ sig. fig.}) \Rightarrow $ answer is (B).$

Physics question on centripetal force (1 Viewer)

zenia99

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InteGrand

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