halp integrate pls (1 Viewer)

Nailgun · Feb 24, 2016

Can someone compute this lol and confirm I'm not going crazy
In the solutions the answer comes out to 5/4, I have no idea what they did
It's such a simple integral too...

$\int _{ -1 }^{ 0 }{ (3x+2)^{ 3 } } dx$

Sien · Feb 24, 2016

I got 5/4 lol

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InteGrand · Feb 24, 2016

Nailgun said:
Can someone compute this lol and confirm I'm not going crazy
In the solutions the answer comes out to 5/4, I have no idea what they did
It's such a simple integral too...

$\int _{ -1 }^{ 0 }{ (3x+2)^{ 3 } } dx$

$\noindent We have$

$\begin{align*} \int _{ -1 }^{ 0 }{ (3x+2)^{ 3 } } \text{ d}x &= \left[\frac{(3x+2)^{4}}{3\times 4} \right]_{ -1 }^{ 0 } \\ &= \frac{1}{12}\Big{[}(3x+2)^{4} \Big{]}_{ -1 }^{ 0 } \\ &= \frac{1}{12}\left(2^4 - (-1)^4\right) \\ &= \frac{15\color{cyan}\div 3 \color{black}}{12 \color{cyan}\div 3 \color{black}} \\ &= \frac{5}{4}. \end{align*}$

Nailgun · Feb 24, 2016

OH JOKES

lol I realised what I did
I thought the x=0 part was just 0 ahaha
okay thanks lol

here i come band 3 lol

halp integrate pls (1 Viewer)

Nailgun

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Sien

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InteGrand

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Nailgun

Cole World

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