First Year Mathematics A (Differentiation & Linear Algebra) (1 Viewer)

iforgotmyname · Jun 8, 2016

Re: MATH1131 help thread

Flop21 said:
No I cannot.

Did you screw up class test/maple

Flop21 · Jun 8, 2016

Re: MATH1131 help thread

iforgotmyname said:
Did you screw up class test/maple

yeah

nevermind that lol, I worked out if I get like 49+ in exam or something similar I pass. Which is better than I thought it would be.

Mr_Kap · Jun 9, 2016

Re: MATH1131 help thread

Flop21 said:
yeah

nevermind that lol, I worked out if I get like 49+ in exam or something similar I pass. Which is better than I thought it would be.

Do you mean 49/64 or 49%. I hope you mean 49% otherwise riperinio.

i"m in the same boat as you for math. been doing comp resume all weekend, and then studying linked lists past few days. So today is first day I'm visiting maths study. Im praying for a miracle...but hey, like i said on fb, at least we've got the L'hospital if we get rekd. ahahah.

Flop21 · Jun 9, 2016

Re: MATH1131 help thread

Mr_Kap said:
Do you mean 49/64 or 49%. I hope you mean 49% otherwise riperinio.

i"m in the same boat as you for math. been doing comp resume all weekend, and then studying linked lists past few days. So today is first day I'm visiting maths study. Im praying for a miracle...but hey, like i said on fb, at least we've got the L'hospital if we get rekd. ahahah.

Yeah 49% haha.

Yeaaaaah exact same boat as you (at least I got the joy of passing linked lists finally). Good luck, hopefully we won't need the l'hospital lol.

leehuan · Jun 9, 2016

Re: MATH1131 help thread

Final exam is out of 80. 40/80 doesn't seem so hard...

iforgotmyname · Jun 9, 2016

Re: MATH1131 help thread

leehuan said:
Final exam is out of 80. 40/80 doesn't seem so hard...

Step back mr 4u, dont wanna end up in le'hospital

leehuan · Jun 9, 2016

Re: MATH1131 help thread

iforgotmyname said:
Step back mr 4u, dont wanna end up in le'hospital

They told me 60/80 was what's typically needed to get an HD in MATH1151. So that's what I'm aiming for.

I think my biggest fear in the exam room will be time control. I generally get 68-73/80 for each past paper I do, but it takes me a while to actually do the paper. Gotta start mimicking exam conditions.

P.S. just cause 4u helps doesn't mean 4u was a need to do well

Red_of_Head · Jun 9, 2016

Re: MATH1131 help thread

Heads up, a livestream for MATH1131/MATH1141 revision from 1200-1400 here: https://www.youtube.com/watch?v=JeuDb4oWhus

First hour is easier stuff, next hour gets harder (aimed at 1141).

Flop21 · Jun 9, 2016

Re: MATH1131 help thread

Red_of_Head said:
Heads up, a livestream for MATH1131/MATH1141 revision from 1200-1400 here: https://www.youtube.com/watch?v=JeuDb4oWhus

First hour is easier stuff, next hour gets harder (aimed at 1141).

Yeah it's good stuff. I've spent yesterday and today going through the first 1.5 hour.

[math school pls replace tutorials with these types of videos]

Red_of_Head · Jun 9, 2016

Re: MATH1131 help thread

Flop21 said:
Yeah it's good stuff. I've spent yesterday and today going through the first 1.5 hour.

[math school pls replace tutorials with these types of videos]

[Physics school please give us tutorials]

I agree, these get through about 3x the content.

Flop21 · Jun 9, 2016

Re: MATH1131 help thread

When we sub x = 1 into -Pi^2*cos(Pi*x)

why does it equal Pi^2?

InteGrand · Jun 9, 2016

Re: MATH1131 help thread

Flop21 said:
When we sub x = 1 into -Pi^2*cos(Pi*x)

why does it equal Pi^2?

$\noindent Because $\cos \pi=-1$.$

Red_of_Head · Jun 9, 2016

Re: MATH1131 help thread

Flop21 said:
When we sub x = 1 into -Pi^2*cos(Pi*x)

why does it equal Pi^2?

cos(pi)=-1

Flop21 · Jun 9, 2016

Re: MATH1131 help thread

Red_of_Head said:
cos(pi)=-1

Oh right thanks, I get it now because you can see it on a graph, or you can see it on your calculator in radian mode (had it on dec).

leehuan · Jun 9, 2016

Re: MATH1131 help thread

Flop21 said:
Oh right thanks, I get it now because you can see it on a graph, or you can see it on your calculator in radian mode (had it on dec).

At uni level maths I reckon you should just leave your calculator on rads.

Flop21 · Jun 9, 2016

Re: MATH1131 help thread

How do I know whether to use the dot product rules or the cross product rules in a question involving the angle between 2 vectors?

InteGrand · Jun 9, 2016

Re: MATH1131 help thread

Flop21 said:
How do I know whether to use the dot product rules or the cross product rules in a question involving the angle between 2 vectors?

$\noindent What's the question? Usually dot product is better because it's faster to compute. The cosine of the angle between the two vectors is given by $\cos \theta = \frac{\vec{a}\cdot \vec{b}}{\left \|\vec{a}\right\|\left \|\vec{b}\right\|}$.$

Flop21 · Jun 9, 2016

Re: MATH1131 help thread

Can someone show me working of out this integral by u-substitution?

1/(1 + root(x)) dx

Thanks.

leehuan · Jun 9, 2016

Re: MATH1131 help thread

$u=\sqrt{x}$ or alternatively $u^2=x\\ $So $2u\, du = dx$

$\int{\frac{1}{1+\sqrt{x}}dx}\\ = 2\int{\frac{u}{1+u}du}\\ =2\int{\left(1-\frac{1}{1+u}\right)du}\\ =2u - 2\ln{|1+u|}+C \\ =2\sqrt{x} + 2\ln{(\sqrt{x}+1)}+C$

Flop21 · Jun 9, 2016

Re: MATH1131 help thread

If I use u = 1 + root(x)...

x = (u-1)^2
dx = 2u-2

Then putting into the original thing, integrate (2u-2)/u...

can someone take it from here and finish it off? I get very close to the answer but don't get it, I think because I'm doing incorrect algebra after that last step ^.

First Year Mathematics A (Differentiation & Linear Algebra) (1 Viewer)

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