Trig identity question (1 Viewer)

[highshill]

Does any one how to solve this I know what do but keep making a mistake somewhere
Prove:
(sins-cosx)= sinx-cosx-2sinxcosx+2sinxcos^2x

 

[1729]

Does any one how to solve this I know what do but keep making a mistake somewhere
Prove:
(sins-cosx)= sinx-cosx-2sinxcosx+2sinxcos^2x

Double-check the LHS is written correctly ('sins', and there may be an exponent because there are parentheses)

 

[highshill]

It was the LHS to the power of three sorry I typed it wrong

 

[He-Mann]

Identity is false for all integer powers (of LHS).

 

[He-Mann]

I believe there is another typo on the RHS. Expand via binomial theorem and use Pythagorean trig identities to get