glazebrook
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HSC 1991 I think! Can anyone help? (1 Viewer)
- Thread starter glazebrook
- Start date
i) 
Since
,
You can use long division and then divide by
(since 
) to obtain the desired result. It's rather unintuitive, though.
________________________________________________________________________________________________________________________
ii) Consider the expansions of
^2 \,$and$\, \left( z + \frac{1}{z}\right)^3)
.
________________________________________________________________________________________________________________________
iii) There are six solutions to the equation in part i). By performing the substitution in ii), you've reduced it down to three, by making three of those solutions the same as the other three.
Find these three unique solutions and use the product of roots and the properties of
in the first and second quadrants to obtain the answer.
Since
You can use long division and then divide by
________________________________________________________________________________________________________________________
ii) Consider the expansions of
________________________________________________________________________________________________________________________
iii) There are six solutions to the equation in part i). By performing the substitution in ii), you've reduced it down to three, by making three of those solutions the same as the other three.
Find these three unique solutions and use the product of roots and the properties of
KAIO7
Member
HSC 1992 Q7
If you are interested in these type of questions, I'd recommend checking out coroneos (The supplementary book), it has a lot of similar/Interesting questions.
