Given any titration curve, a suitable indicator is one whose pH range is entirely within the "vertical" section of the curve, and ideally where the pH range includes the pH at the equivalence point.
For this curve, and going by eye, bromothymol blue (pH range 6.0 to 7.6) would be a suitable indicator.
If no table of indicators was given, I would accept methyl red (pH range 4.8 to 6.0) and phenol red (pH range 6.8 to 8.4) as these also fall into the vertical range of the pH curve.
I would not give an answer at all along the lines of the one provided (I presume) from the solutions, for several reasons:
- Methyl orange, with its pH range of 3.2 to 4.4, is obviously unsuitable for the given system based on the pH curve provided
- Discussing the pH of the equivalence point by reference to the nature of the acid and base used is simply poor technique. The equivalence point occurs when the acid and base are present in their stoichiometric ratio. Thus, it represents the point where the acid and base have (theoretically) completely reacted and so are no longer present in the system - so why would they determine the pH? The answer is, they wouldn't and don't.
- The substances that are present at the equivalence point are the salt formed and water, and so the pH should be rationalised in terms of those substances. So, for example, suppose we had a strong acid / weak base titration like nitric acid and ammonia. At the equivalence point, the salt present is ammonium nitrate and it is a weak acid as the hydrolysis (reaction with water) of the ammonium ion produces some hydronium ions which cause the pH to decrease, via: NH4+(aq) + H2O(l) <----> NH3(aq) + H3O+(aq) The nitrate ion, being the conjugate base of a strong acid, does not hydrolyse in water to any significant extent and so the pH at the equivalence point is in the acidic range solely because of the weak acid nature of the ammonium ion.
- You may notice that, in (3), I did not choose the system in this question. That is for a very good reason... it is not clear what the system is!
As
@thush@decode has commented, the curve does not match what would be expected for a strong acid / weak base titration such as the one that I have described. There are two reasons for this.
Firstly, most titration curves are given for 1:1 reactions. For non-1:1 case, there are typically multiple end points. For example, if I titrated 15.00 mL of 0.1000 M phosphoric acid (conical flask) with 0.1000 M sodium hydroxide, I would get equivalence points at 15.00 mL, 30.00 mL, and 45.00 mL, corresponding to the reactions:
H
3PO
4 + NaOH ----> NaH
2PO
4 + H
2O
NaH
2PO
4 + NaOH ----> Na
2HPO
4 + H
2O
Na
2HPO
4 + NaOH ----> Na
3PO
4 + H
2O
The pHs at the equivalence points would be at something like 4, 9.5, and 13, reflecting that the dihydrogenphosphate ion is a weak acid and that the hydrogenphosphate and phosphate ions are weak bases.
In the case of sodium carbonate, adding a strong acid can protonate to the hydrogencarbonate ion and again to carbonic acid, so there are two stages. But, carbonic acid exists in equilibrium with carbon dioxide and water, so the system in the question appears to me to be mixing the sought reaction
Na
2CO
3(aq) + HCl(aq) ----> NaHCO
3(aq) + NaCl(aq)
with the alternative
Na
2CO
3(aq) + 2 HCl(aq) ----> 2 NaCl(aq) + CO
2(g) + H
2O(l)
It is my guess that the graph given is not based on empirical data but rather a simulation (you can see how the graph has joined plotted points with straight lines). That simulation would use the pKa values and ignore the likely production of CO
2 gas to get a theoretical result that is flawed due to relevant factors being neglected. I doubt a teacher would ever get students to titrate an acid into a carbonate solution for exactly this reason. And this graph shows adding carbonate ions into a solution where hydronium ions are initially in massive excess, and asking that only the protonation occurs! Not likely.