If on the first day he lays ‘k’ bricks, second day he lays ‘2k’ bricks for a total of (1+2)k bricks, then by the end of the tenth day, he will have laid the arithmetic sum of the first ten integers multiplied by k:
(1+2+3+4+5+6+7+8+9+10)k = k(10x11)/2 = 55k
For 55k = 1100, k = 20
For the question, the median is still 12.
The median is the central score when you line up all the scores in either increasing or decreasing order. By adding the same number (two) of scores which are less than (4,7) and greater than (13,14) the median (12), the median value doesn’t change.