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Maths Ext 2 Predictions/Thoughts (2 Viewers)

notme123

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dont they choose a question and deduct marks if not rounded, otherwise it doesnt matter right? lets pray it was the shm one cuz i know i rounded for that

by the way what did people get for that. i got less than 1 i know, like .3s maybe i forgot
 

dbramley

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dont they choose a question and deduct marks if not rounded, otherwise it doesnt matter right? lets pray it was the shm one cuz i know i rounded for that

by the way what did people get for that. i got less than 1 i know
Not sure about maths I know that’s the case for physics specifically
 

notme123

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asked for tof and also had to get rid of t's
i thought it said during the time of flight there 2 values of t, not specifically find time of flight. when you sub the time of flight youre only looking at that point unless i screwed up again
 

zakoht

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congrats to whoever solved the 5 marker in its entirety, i got like half way then the algebra was getting horrendous
The algebra genuinely was so messy, but it all tidied up really nicely if you stuck through. Pretty much everything cancelled beautifully.
 

tito981

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wasnt too difficult, it will a bit harder than last yr. I think ppl arent used to the question formats
 

Siwel

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i thought it said during the time of flight, not specifically find time of flight
yeah but you had t's left over in the dot product so to get rid of them i found tof, then when solving for theta 1 is 0, the other you use quad for and its a nice pi/something
 

Eagle Mum

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Was the last question the graph of xtanx?
It’s an inequality, so you still have to work out what regions to shade. DS didn’t get to that bit. Did everything else but didn’t have time to check the rest of the paper, so could have lost marks on ‘silly mistakes’ as he did with the Adv Maths & Ext 1 papers in previous years.
 

juju1234

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im venting here so excuse my scattered thoughts but wtf was that exam.?!?! every past trial i did was way easier. it got to the point during this that i started making things up, started working up the page and skipped lines of working for my proofs in the chance that the marker would be tired asf marking and just give me some marks. q15 and 16 were literally just creative writing exercises for me. also i needed so many extra booklets but the supervisor was taking her sweet time bringing them over :| how hard would it hv been to double up the pages in each question booklet like yuhh save the environment but nah i hate nesa
 

Siwel

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im venting here so excuse my scattered thoughts but wtf was that exam.?!?! every past trial i did was way easier. it got to the point during this that i started making things up, started working up the page and skipped lines of working for my proofs in the chance that the marker would be tired asf marking and just give me some marks. q15 and 16 were literally just creative writing exercises for me. also i needed so many extra booklets but the supervisor was taking her sweet time bringing them over :| how hard would it hv been to double up the pages in each question booklet like yuhh save the environment but nah i hate nesa
compared to last years proofs they really just destroyed us
 

zakoht

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do you have a solution
Pretty much if you're looking for perpendicular values, you can treat it as Pythagorean, I derived the velocity vector in X and y and I created a third equation for both pos and velocity in the form of c² = ✓(a²+b²), I then multipled those two third equations (velocity and pos) and let them = 0 for perpendicular. From then on I just solved got rid of all the nasty algebra and factored it so it was out of Squareroots and them you had two values for theta.
 

notme123

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Pretty much if you're looking for perpendicular values, you can treat it as Pythagorean, I derived the velocity vector in X and y and I created a third equation for both pos and velocity in the form of c² = ✓(a²+b²), I then multipled those two third equations (velocity and pos) and let them = 0 for perpendicular. From then on I just solved got rid of all the nasty algebra and factored it so it was out of Squareroots and them you had two values for theta.
ye idk ill just wait till the official solutions are up haha youre too smart
 

Siwel

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Pretty much if you're looking for perpendicular values, you can treat it as Pythagorean, I derived the velocity vector in X and y and I created a third equation for both pos and velocity in the form of c² = ✓(a²+b²), I then multipled those two third equations (velocity and pos) and let them = 0 for perpendicular. From then on I just solved got rid of all the nasty algebra and factored it so it was out of Squareroots and them you had two values for theta.
you didnt have theta=0?
 

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