A particle of mass 20 kg is suspended by two strings attached to two points in the same horizontal plane. If the two strings make angles of 20° and 45° respectively to the horizontal, calculate the magnitude of the tension in each string, in newtons correct to 2 decimal places.
Below is the working to this version of the question:
A particle of mass 20 kg is suspended by two strings attached to two points in the same horizontal plane. If the two strings make angles of 20° and 45° respectively to the horizontal, calculate the magnitude of the tension in each string, in newtons correct to 2 decimal places.
Below is the working to this version of the question:
I usually get an equation for ΣFx and ΣFy like the image you sent, then I go for simultaneous equations but I'm not sure how to solve it simultaneously given the angles in the question (27° and 42°)
I usually get an equation for ΣFx and ΣFy like the image you sent, then I go for simultaneous equations but I'm not sure how to solve it simultaneously given the angles in the question (27° and 42°)
There is a very sharp solution here you see how the difference between 42 degrees and 27 degrees makes 15 degrees right. Time to get creative and use what you know which is
or in this case use this to your advantage and using the fact that g is something. Give that a try @broilingshroom