Run hard@thehsc
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Anyways would you have to multiply the volume of revolution by two to account for the positive and negative root of the function?
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Why is this like this? (2 Viewers)
- Thread starter Run hard@thehsc
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Anyways would you have to multiply the volume of revolution by two to account for the positive and negative root of the function?
mmmmmmmmaaaaaaa
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No, as seen through the formula below, when rotating about x-axis, you use a 'y^2'.
- All you need to do is divide by (x^2+4) and use y^2=9/(x^2+4) to get your answer
Hope it helps
- All you need to do is divide by (x^2+4) and use y^2=9/(x^2+4) to get your answer
Hope it helps
5uckerberg
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I reckon your question came from a place of anxiety because when you saw the x squared and y squared you were like huh what do I do.
Fear not because all you have to do is use the formula from a cone and then notice that the axis of rotation is the height and the axis that is perpendicular is the radius.
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