wanna confirm ans (1 Viewer)

vishnay · Apr 11, 2022

i got $\frac{x^2e^{x^2}}{2}-\frac{e^{x^2}}{2}+C$

Lith_30 · Apr 11, 2022

You can use this website https://www.integral-calculator.com/ if you want a fast way to check answers.

5uckerberg · Apr 11, 2022

Is this integration by parts.
What is the differentiation of $e^{x^{2}}$ ? Knowing that we can now have
$\int{x^{3}e^{x^{2}}}dx=\frac{1}{2}\int{2x^{3}e^{x^{2}}}dx=\frac{1}{2}\int{x^{2}\cdot{2xe^{x^{2}}}}dx$ .
There, we will have $\frac{1}{2}\int{x^{2}\cdot{2xe^{x^{2}}}}dx=\frac{1}{2}x^{2}e^{x^{2}}-\int{xe^{x^{2}}}dx$
Note that $\int{xe^{x^{2}}}dx=\frac{1}{2}\int{2xe^{x^{2}}}dx$ . So our final answer should be
$\frac{e^{x^{2}}}{2}\left(x^{2}-1\right)$

5uckerberg · Apr 11, 2022

Run hard@thehsc said:
View attachment 35441

What was your answer?

Run hard@thehsc · Apr 14, 2022

5uckerberg said:
What was your answer?

oh ok ye I got that. Thanks!!! And yh it is integration by parts

wanna confirm ans (1 Viewer)

Run hard@thehsc

Well-Known Member

vishnay

God

Lith_30

o_o

5uckerberg

Well-Known Member

5uckerberg

Well-Known Member

Run hard@thehsc

Well-Known Member

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