I have a few more proof qs
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for this i get to 3q=2p but theres nothing else to do (I put it into prime factors and equated the powers)
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I tried using (k-1)k(k+1) using cases of k odd and even but it doesn't come out
Ill skip the "formal proof" thing since thats smthn i assume u can do
1)
Clearly rational, its 3/2. Find a way to prove that its rational. (Hint; "if X is rational then it can be written in the form ... and because there exists ... such this is true then X must be rational")
2)
Contrapositive here. If a divides b then a divides bc. Should be straightforward. I like to thing of divides as "a factor of" since thats less confusing.
3)
product of three consecutive integers can be represented as n(n+1)(n+2). Consider what happens if n were to be divided by 3, it would either divide perfectly ( n=3k) or would have a remainder (n=3k+1,3k+2). Use proof by cases and figure this one out, should be straightforward.