'...for all values of x'??? (1 Viewer)

[jane1820]

what does that mean? do i solve then sub in random variables for x?


[Cambridge Math Advanced Year 11: 3A, 17.a]

 

[MoeyNeeds90+]

what does that mean? do i solve then sub in random variables for x?
View attachment 46536

[Cambridge Math Advanced Year 11: 3A, 17.a]

sub then simplify then use the answer simplified to compare against the given function

 

[ButteryNucleotide]

u can format it like this:

RTP: f(x)=f(-x)

LHS = f(x)
= x^4 + 2x^2 + 3

RHS = f(-x)
= (-x)^4 + 2(-x)^2 + 3
= x^4 + 2x^2 + 3
= LHS .•. f(x)=f(-x)

 

[jane1820]

u can format it like this:

RTP: f(x)=f(-x)

LHS = f(x)
= x^4 + 2x^2 + 3

RHS = f(-x)
= (-x)^4 + 2(-x)^2 + 3
= x^4 + 2x^2 + 3
= LHS .•. f(x)=f(-x)

yes i know how to solve it i just dont know what was meant by 'all values of x' like do i sub in a variable to prove changing x will still prove f(x)=f(-x)

 

[C2H6O]

yes i know how to solve it i just dont know what was meant by 'all values of x' like do i sub in a variable to prove changing x will still prove f(x)=f(-x)

Idk if you already know what it means now, but just in case: by subbing in x (or -x) and treating it normally to complete the proof, you will have automatically solved for every number (bc x could be every number)