Recent content by flavurr

Re: HSC 2016 2U Marathon a^o=X => loga(X)=o a^g= Y => loga(Y)=g a^l=XY => loga(XY)=l a^l = a^o * a^g (when multiplying by same base add exponents) a^l = a^o+g (same base, exponents must equal each other) l = o+g (substitute back into log form) loga(XY) = loga(X)+loga(Y) Im going to get...

Re: HSC 2015 3U Marathon Sorry for how its set out and all. And I dont know if theres a proper ext way of doing it

Re: HSC 2015 3U Marathon Is the answer possibly x/(x+1) ?

squared

How did you go from tan^2(theta) <1 to -1 < tan(theta) <1 ? sorry im sounding silly here

r=-tan^2(theta) For what values of theta between the interval -pi/2 < theta < pi/2 does the limiting sum exist?

Re: HSC 2015 2U Marathon feel like i did this horribly wrong but is it 12/84?

If an object is speeding up, its acceleration is in the same direction as its motion. SO since v<0 and a<0 the particle is speeding up in the negative direction. On the contrary, if v>0 and a>0 then the particle is speeding up in the positive direction

98.65

How was the 2U for anyone who did it?

Did you only need help with the driving q?

Re: HSC 2015 4U Marathon I got 7pi, care to show working out?

Re: HSC 2015 2U Marathon Q. If the continuous function f(x) is an even function, prove that f'(x) is an odd function

Re: HSC 2015 2U Marathon dy/dx=m= 1/2squareroot(x-4) Simultaneously solve y=mx and y=squareroot(x-4) subbing in m=1/2squareroot(x-4) x/2squareroot(x-4)=squareroot(x-4) x= 2(x-4) x=8

Re: HSC 2015 2U Marathon hey dr wouldn't it be 20/52 * 4/51 * 3/50 * 2/49 *1/48 as once you pick the first card, there is only a possibility of 4/51 to pick the 2nd of that same suit then 3/50 to pick the 3rd of that same suit ect