Recent content by xXnukerrrXx

Fermentation by the yeast upon the glucose ceases at a certain concentration of ethanol. (i forgot the concentration level). Any concentration higher, they yeast could not survive as a result dies. Hence fermentation ceases and mass changes stops.

soooo... does anyone know how to do this?

Question 13) ANS: bii)16m iii)112 degrees

Hey guys, just wondering how do you do collision questions in projectile motion. I need help on Year 12 Cembridge Ex 3G Q 13b). Thanks

When can you drop terms if they are getting in the way of your proof? Induction (summing, divisibility and inequalities)

if n is even prove n^2+2n is divisble by 8 thanks

For the GP (\sqrt5+\sqrt3)+(\sqrt5-\sqrt3)+... verify S_\infty =T_1+\frac{1}{3}\sqrt3

In my opinion, you should not use the word thesis within the essay itself; because your essay really is the thesis arguing for or against the question. Following from the comments above, theres is alot of retelling and use your quotes sparingly. Quotes are really to reinforce your argument...

Can anyone show me how to do Question 26b) in the 2011 HSC Chemistry paper? I am very confused :S. Thanks for your help ^^ http://www.boardofstudies.nsw.edu.au/hsc_exams/hsc2011exams/pdf_doc/2011-hsc-exam-chemistry.pdf

Qs: Change tan x = sin x/cos x show that if you integrate tan x from 0 to pi/4 the answer would be 1/2 ln(2)

thanks didnt use the calculator couldnt do it :L

How do i solve this provided within the domain of 0<=x<=2pi tan x =squareroot(2)-1 thanks =D

dunno if this would help? (1) x=t+(1/t) (2) y=t^2+(1/t^2) similarly to the property a^2+b^2=(a+b)^2-2ab (1) x^2=(t+(1/t))^2=t^2+(1/t^2)+2 therefore to get t^2+(1/t^2) we minus the 2 x^2-2=t^2+(1/t^2) substitute t^2+(1/t^2) in equation (2) y=x^2-2

the attachment link is dead just saying.

(1) x=t+(1/t) (2) y=t^2+(1/t^2) similarly to the property a^2+b^2=(a+b)^2-2ab (1) x^2=(t+(1/t))^2=t^2+(1/t^2)+2 therefore to get t^2+(1/t^2) we minus the 2 x^2-2=t^2+(1/t^2) substitute t^2+(1/t^2) in equation (2) y=x^2-2