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Thanks so much for the explanation and advice! I really appreciate it :)

Thanks for that! I guess the reason why the GPA concerns me is because I'm hoping to transfer to another course (either postgraduate or undergraduate medicine in particular) and one of the factors for entry was your GPA so I guess I am kinda concerned about it. Just a quick question though -...

Hey there, I think this has been posted somewhere before but I was just wondering whether I should do the normal or advanced maths units in first year - in particular, the one for 'Linear Algebra' and 'Calculus of One Variable'. My majors will be Neuroscience and Data Science. I've heard that...

Just out of interest, has anyone seen Clannad ~ After Story ~ ?

Hey man, I'm really sorry to hear you're going through all of that. I can definitely understand how stressful the HSC can be and I'll be honest with you, I too was pretty upset during the beginning of Year 12 as I didn't have a very good start to the HSC either. I didn't do much in the...

No worries. I think what happens is you have KOH as your electrolyte in a porous medium within the middle of the button cell. Zinc acts as an anode on one end of the cell and silver oxide is the cathode at the other end of the cell. The Zinc basically reacts with the OH- ions from the KOH...

Hopefully this helps! Reaction at anode which is composed on Zn Oxidation: Zn(s) + 2OH-(aq) --> ZnO(s) + H2O(l) + 2e- Reaction at cathode which is composed of Ag2O Reduction: Ag2O(s) + H2O(l) + 2e- --> 2Ag(s) + 2OH-(aq) And overall reaction is, Zn(s) + Ag2O(s) --> 2Ag(s) +...

What I did was trying to get ahead of the class in terms of theory and doing practice questions as soon as I learnt something new - I thought it was rather effective for me. Also, I think I had mid-years around the middle of the term so I tried to practice papers every now and then and...

Yeah as Jazz said, I think it's called an initiator instead. The initiator is essentially an organic peroxide such as benzoyl peroxide. Basically an initiator molecule 'splits' to form free radicals. These free radicals are highly reactive due to its unpaired electron and can react readily...

Year 11 for me was more like a 'practice-run' for Year 12 haha. I was basically experimenting with different study methods whilst also trying to get into the habit of having a well-rounded schedule (e.g. doing sports and other stuff). Unfortunately, the only subject that I did in common with you...

Haha I remember doing this back when I did my creative. This is what I basically did: - Ensure that your character interactions do not feel contrived - Make sure that every sentence you write contributes to the atmosphere and/or progression of the story. If it doesn't, its better to take it...

Your timetable looks really good and organised to be honest, especially when you're only in Year 11! However, in my opinion, the weekends seem a little packed, especially since it looks like you have three or something different tuition subjects on Saturday. Just remember that although Year 11...

I'm pretty sure ATAR doesn't matter at all if you're thinking of doing medicine as a postgraduate pathway. For Melbourne Uni, the most common pathway would probably be to take a Bachelor of Biomedicine (or any other degree), get a high GPA then do well in the GAMSAT and interview to get into...

Hey there, Please don't worry too much - I didn't study that much during the Summer holidays as well. My best advice would be to start studying as soon as possible - that is, catch up on all the theory, make succinct notes and do some practice questions if possible. If you know when you have to...

I think 'neutron-rich' and 'neutron deficient' just refers to the neutron : proton ratio of the nuclei. If there were much more neutrons than protons in a nuclei, then it would most likely be unstable and also be considered as 'neutron-rich' (due to the excess of neutrons). You can probably...

This is what I got. $ 2^{2x} -2(2^x) \leq -1$ $ Let u= 2^x $ $ ∴ Using substitution... $ u^2 - 2u \leq -1 u^2 -2u + 1 \leq 0 (u-1)^2 \leq 0 $ When you graph the above inequality, you'll see that the parabola has a value equal to 0 at u = 1. It's never less than 0 though...

Done. Seems like a great event! :)

Firstly, congratulations for scoring 98 in 2U! I was just on the ATAR calculator websites and it seems that a 4U mark of 91 or 92 is equivalent to a 98 in 2U. So it seems that if you feel rather comfortable at scoring in the E4 range for 4U then I would recommend doing 4U. If you get higher...

Yeah, I would remember statistics and stuff - at least that's what I did for my Chemistry preparation. However, in your exams, they will most likely not ask you about specific events/data. For example, they won't ask "Assess how quantitative analysis of Antarctic ice core sample by the CSIRO...

Re: Nuclear chemistry question! Easychem answer For Chemistry, no not really - it's not in the current HSC syllabus (at least for the core modules as I'm not sure about the option topics). For Physics, if you do Quanta to Quarks, then yes, you will need to know about nuclear fission (not sure...