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if it helps here's a document made by Stuart Palmer (he wrote a few of the cambridge textbooks) detailing which hsc advanced and extension questions are defunct with the new syllabus Google doc

you might have luck asking your school for past trial papers. ive heard that some schools are fine with giving students their past trial papers

oh word, any advice on learning this stuff early (preferably without buying a textbook yet) because i was thinking about doing 4u next year

isnt part 2 (e-1)? i might be tripping but isnt 1/1! + 1/2! + 1/3! +.... = e - 1 ? because the sum from n=0 to infinity of 1/n! = e or is it in reference to the previous sum in part i

here's how i remember how to do these ones 1. what are we trying to find? (here we want to find the increase (rate of change) in a cube's volume when it's side length is 150mm - this is the same as dV/dt) 1. what differentials are we given? (here we are given the derivative of the side length...

I think november 14, 2013 as thats the earliest date i can find it released

probably something with snells law. my practical task is determining the refractive index of light through a perspex block

i thought sec(pi/2) was undefined?

👽👽👽 (sorry ignore top of the page with cosh inverse)

hope this helps

if there are any vertical asymptotes in a function you cant take the derivative there, also if you take the derivative of a function and then plug in an x value where you end up with a zero in the denominator youll end up with a vertical tangent, e.g f(x) = x^(1/3) f'(x) = 1/(3x^(2/3)), and...

if you dont mind me asking how did you find worked solutions for cambridge? i had no idea they did worked solutions

so pretty much we did a u-sub, and what i did was this: i let u = 2x-1 now my original integral had the bounds from 1 to 2 so when i did a u-sub here, i have to now say that my 'new' upper bound will be 2x-1, where 'x' was my old upper bound. So now i get a new upper bound as 2(2) - 1 = 3 i do...

Here's my working: so if polynomial P(x) (lets just call it that) has two roots at x=2 we can write P(x) as (x-2)(x-2)(x-d) (where 'd' is the unknown third root) this will come in handy later So for cubics in the form ax^3 + bx^2 +cx +d = 0, And denoting the roots as α, β and γ, we know that α +...

hope this helps

hehehe

for part (iii), think about at what point on the circle will the tangent line be undefined (a vertical line as the slope) recall that for eq of circles, x^2 + y^2 = r^2 so we know that -3 and 3 are the radius of the circle on the x axis the slope at these points would be a vertical line, hence...

our school uses edrolo. its great for maths and physics and probably for bio and chem as well. it offers summarised notes and the videos follow the syllabus structure with multiple choice questions throughout each lesson