Re: HSC 2013 3U Marathon Thread
Question:
$Without evaluating the intergal,I = $\int_{\frac{1}{2}}^1 ln(x)dx,$ is it less or greater than zero?
Negative as the "area" (not sure how else to put it, but the region there..) between 0.5 and 1 would be negative.
Therefore less than zero...