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if you sub in 0 you get 4=0 :P ... try again.

But it's u -\sqrt{u}+3= 0 u-3 = \sqrt{u} (u-3)^2=u u^2-7u +9 =0

pls learn Latex... Here's one I made (No year 11 + help pls) $ Solve for x $ 4x^4+6x^3+3x^2+6x+4=0

u- \sqrt{4} +3 = 0 ? u= \sqrt{4} -3 lol ?

Just remember if going for m^2 to cm^2 you dont multiply by 100 but rather 100^2.

Will answer this in inbox soon busy at the moment. If I look up the arabic im 99% sure I wont see the word lying or lie or anything on those lines. Also in wars as I said tricking the opponent is allowed. It is also expected

Mathematical and logical fallacy. Firstly what you are saying is like in induction when you have to prove for all n values. How I see your argument "If n=1 is true and n=2 is true then n=anything must be true." Which is not the case and thus you cannot make the conclusion you made. Also we have...

The advantages are outweighed by the disadvantages.

lol integrand man what are you doing you made it look so hard ahhaha x= 0.211212121 100x=21.12121212.. 10000x=2112.12121212 (10000-100)x=2112-21 x=\frac{697}{3300}

My English teacher was a straight savage what can I say...

Re: Flop math question thread If it doesn't appear in the HSC then its not 2u :P

This is usually associated with sexual things not normal things.

You savage!

Re: Flop math question thread And also \lim_{x \rightarrow 0 }\frac{\sin{x}}{x} = 1

Idk but Drsoccerball's tutoring is pretty good check him out ! LOL jks im crap.

Re: MX2 2016 Integration Marathon Relax I wanted to use my partial fractions method.

Re: Flop math question thread 2 Unit method: Let u = x^2 solve the results and present it in the form : (X-A)(X-B)(X-C)(X-D) If it's not integers then expand the brackets you think will cause integers.

Re: MX2 2016 Integration Marathon We can make use of my partial fractions formula : I=\frac{1}{2}\int_0^1{\frac{1}{\sqrt{u+2}}- \frac{\sqrt{u+2}}{(u+2)+1}}dx $ After $ u=x^2

Re: MX2 2016 Integration Marathon .

Re: MX2 2016 Integration Marathon We could use the formula we proved on the previous page.