It could mean find the sum of the n^2 terms (although they are in terms of x)?
In this case 1) would be the coefficient of x^2, so the answer is 3.
But that question just seams faulty. Could you say where you got these questions and under what exercise they were under (ie Binomial Coefficients...
I have all the AMC papers from 2002 to 2008 in all 3 levels (Junior, Intermediate and Senior) and solutions to 2008 (in Chinese =P) and 2007 (in English =)
Add to this a Silver medal at the 2008 IMO, a Gold and 2 Silver Asian Pacific Mathematical Olympiad medals, 3 Gold Australian Mathematical Olympiad certificates and 4 Australian Mathematics Competition medals! ... just to mention a few.
Pure genius indeed!
Also, just a tip for this years Westpac Maths comp. It is useful to know important facts about the number that is the year in which the paper is set ie 2009. It is useful to know about the number 2009 because Australian Mathematics Competitions will almost always have a question that has the...
I know! Its crazy!
I have pretty much procrastinated throughout the first half of these holidays. Now i have three textbooks to go though and finish in the rest of the holidays!
The problem states that "the centre of the circle is inside the 15-gon". Therefore all the vertices of the 15-gon cannot lie in one semicircle (this is because the centre of the circle would be either on a side of the 15-gon or not be in or on it at all). Furthermore, an acute angled triangle is...
Results =)
Official 2009 IMO site welcome to IMO 2009 Bremen
Official IMO site International Mathematical Olympiad
Australian Mathematics Trust site Australian Mathematics Trust
Cut-Offs for Bronze, Silver and Gold were 14, 22 and 32 points respectively
China came first with 6 gold medals...
Problem 4 proposed by Jan Vonk, Belgium, Peter Vandendriessche, Belgium and Hojoo Lee, Korea
Problem 5 proposed by Bruno Le Floch, France
Problem 6 proposed by Dmitry Khramtsov, Russia
Actually it is not ;)
See the question isnt strictly confined to positive numbers. Dont forget -9 is divisible by 3. So we could, just for argument sake, start at -6, and so this would change the answer.
There is no answer to his question under the current parameters.
So it easy to see the vertical asymptotes occur when x2 - 9 = 0 ie when x = 3 and x = -3
So draw the dotted lines x = 3 and x = -3
Using your calculator it is easy to see that the curve approaches + infinity to the left of -3 and negative infinity to the right of -3. And also the curve...
The whole point of curve sketching is to determine special characteristics of functions and graph them with this information. So instead of memorizing all different types of graphs, you should acquaint yourself with the knowledge and understanding of how to figure out what a function looks like...
Just to add to this:
Problem 1 proposed by Ross Atkins, Australia
Problem 2 proposed by Sergei Berlov, Russia
Problem 3 proposed by Gabriel Carroll, USA