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hahaha i knew u wud be able to do it as i've seen ur posts long time ago and u seem quite high lvl:p that 2003 paper.. i didn't like it, it had 23 marks worth of GEOMETRY+PROBABILITY all up... those are my worst topics lol hope dis yrs paper is not like dat...

^ int. cosxsin^2 x dx =int. sin^2 x d(sinx) =sin^3 x \ 3+C

well u dont' need substitution really.. int. cosxsin²x dx observe that d\dx sinx=cosx then answer is sin³x\3+C

let u=sinx then do it.. answer is sin³x\3+C

http://www.boredofstudies.org/courses/maths/3u/2003_Mathematics_Extension_1_HSC_Sol_Jeff_Geha.pdf

Haven't touched maths for about 6 weeks:( Dunno if I'l be good for tomorrow :(:(

Have you tried the "Resources" section at the main page of this website?

taking gravity, g=-10 Consider the horizontal components: x''=0, x'=60cos45=60\sqrt2, x=60t\sqrt2 Consider the vertical components: y''=-10, y'=-10t+60\sqrt2, y=-5t²+60t\sqrt2+50 set y=0, 5t²-60t\sqrt2-50=0 t=[60\sqrt2 +-sqrt(60²\2-4(5)(-50))]\10 =[60\sqrt2+-sqrt 2800]\10 t=9.534 by...

Question 19 At an air show, a Harrier Jump Jet leaves the ground 200 metres from an observer and rises vertically at the rate of 25 m/sec. At what rate is the observer's angle of elevation of the aircraft changing when the jet is 500 metres above the ground?

nooo way! I hate graphs!! Please be trig!!

I think whether the 2005 exam is "harder" than the 2003 exam depends on the person... I've seen some people say it's harder and some people say it's easier... Personally I think this year was harder than 2003 in terms of length. When I did 2003 for practise I even did better than this:(

Does anyone have some practise questions on... "Normalising" a table and also drawing a Flow Chart of Data FLow Diagram.. etc.. that sort of thing.. yea... anyone can gimme would be nice thx!!:)

ya IPT is stupid, boring AND low scaling:( I have hardly ever touched it throughout the year.. need to cram it all up in the next few days lol

geez there's not many ppl posting here saying they've screwed it compared to the number of people saying they got 90s or 110s LoL:(

Stupid Graphs!! I take too long on them, no time at the end, didn't even attempt Q8 lol #_#

I=int. xe^x dx let u=x and dv\dx=e^x du=dx and v=e^x .: I=xe^x-e^x+C using 'Integration by Parts'

yea i know LoLz I bet he will be in top 10

Goood Luck!! btw u missed out Who_Loves_Maths:p

a)s=ut+(1\2)at² -9.8=24.5(t)-4.9(t)² taking a=-9.8 4.9t²-24.5t-9.8=0 t=[24.5+-sqrt(792.33)]\9.8 =5.37s ignoring the negative value. b)Consider horizontal component... s=ut=24.5(5.37)=131.565m c)horizontal component remains the same throughout the projection. so horizontal impact velocity...

a)v=u+at=50-9.8 (2)=30.4 m\s b)max height is when v=0 so 0=50-9.8t t=50\9.8 so at dis time, max height, S=ut+(1\2)at²=50(50\9.8)-4.9(50\9.8)²=127.55m c)It returns to Earth at v=50-9.8(50\9.8 x 2)=-50 m\s