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double post, but who cares, these forums are like private ones. C = 3 + V³/900 total cost = (3 + V³/900)h, for number of hours h since h = 450/V total cost = (3 + V³/900)*450/V = 1350/V + V^2/2 differentiating, dc/dv = -1350/V^2 + V let this = 0. therefore V = 1350/V^2 V^3 = 1350, V...

OMG rofl 6.45 - 3 = 4.75 hahaha :rofl: thanks soph

monic - coefficient of leading power is 1 even - p(x) = p(-x). the result of this is that all the coefficients of terms with odd powers are zero. a big clue when doing relationships between roots and coefficients.

first, the formula for cost, C, per hour is 3 + kV³, for some number k. therefore, C = 3 + kV³ for one hour. subsituting C = 6.75 and V for 15, 6.75 = 3 + k15³ 4.75 = 3375k k=19/13500 therefore, C = 3 + 19V³/13500 # the second part is a bit more complicated. total cost, c, = (3 +...

aaah okay how could i have forgotten. hehe i'm glad you're not doing the hsc this year.

thank you yip!! only, in the first question, it asks you to show that mx³ - 3x² + 1 = 0 has a double root, not assume it. any ideas? and how did you work out the method to do the second question? i mean, what you did is obviously right, but how would you know this was the way to do it before...

thanks trebla. i say it's tricky because i've done with no queries every other cssa paper in the 2 topics i'm being tested on in the upcoming exams, polynomials and conics. for this paper: q1, b, (ii) "the line y=mx is a tangent to the curve y = 3 - 1/x². Show that the equation mx³ - 3x² + 1...

hey there, does anyone have the solutions to the ext2 2005 CSSA trials? this is one tricky paper. thanks :)

sorry, typo, but you know what i mean. the structure formula may still come up in multiple choice though, esp. in dodgy school trials.

its the PH3B variety.

haha check out question 7, b) i) copy the diagram into your booklet ii) prove that TMSN is a square [8] LOL 8 marks !! most i've seen in a ext2 paper is like .. 4 marks.

aren't general maths and standard english both capped at around 92 or 93?? that means you can't get 100 uai if you do both of those esp if you do other capped subjects. but yeah i agree, subject selection shouldn't be based on capping or scaling, but rather what you're good at, enjoy doing...

Chrono Trigger by a long way, then maybe FF series.

1/Z2 = 1/r2 * cis (-B) therefore, Z1.1/Z2 = r1/r2 * (cosA+isinA)(cosB-isinB) =r1/r2 * (cosAcosB - sinBcosAi + cosAsinBi + sinAsinB) =r1/r2 * [cos(A-B) - (sinBcosAi - cosAsinBi)] =r1/r2 * [cos(A-B) - isin(A-B)]

Re: Harry Potter and the Deathly Hallows what if dumbledore has horcrux(es) of his own? didn't rowling reveal in book 1 dumbledore killed some evil wizard? then he'd appear to have died, but his spirit will linger on - maybe he'll guide harry in this manner.

hmm, well this is my reasoning: 1. suppose it before the acceleration was applied, the object was stationary. now apply a force to the right. it will accelerate to the right, and thus move to the right. 2. suppose a meteor is moving left, suddenly a large mass appears on its right. the gravity...

all are possible.

list A is WEIRD It has that Moszkowski Op72 No2 etude, and Moszkowski lived after Chopin?? So it's not exclusively baroque.

for Caucasians, the healthy range is 20-25 (not sure about Indians, even though Caucasians include Indians) for Asians, the healthy range is 18-23.

did you ever mention you were a pianist in that post? anyway, the Italian Concerto is a lot of work, and very difficult. i mean, it's not technically that demanding but it's very long and that kind of music has no room for variation in tempo, so you're looking at a very long period of...