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m is the gradient, so you would use rise/run to find that, and then just sub it in for m. b is the y-intercept so in instance it would be +2. You can calculate the gradient because the points are (-3,0) and (0,2) so m = (2-0) / (0--3) = 2/3 so therfore m = 2/3 so the graph is y = (2/3) x...

Yeah our teacher said it could be both so its hard to say. I thought social and ethical issues would come in mainly during designing solutions right?

Use a plumb bob, one in a bus and one in your room. Observe that the plumb bob in the non-inertial frame of reference(i.e. an accelerating bus) will not stay vertical (it will tilt backwards)

We argued this the other day but I believe the answer is Designing solutions, because this is where the problem is generally understood and the system designer would create the first prototpye. Keep in mind however that one of teh aims of a prototype is to better understand the problem, so one...

Log x = ln x ...thats the notation thats used (in NSW anyway). Log the the base 10 is just that, its log10x

Let one length of the wire be x cm and the other be (50-x)cm . So the rectangles dimensions are x(3x)=3x2 and the square's dimensions are (50-x)2. I'm not sure if they want the added areas to be a minimum although I think this is how you would do it: Area = 3x2 + (2500 - 100x + x2) dA/dx =...

Thanks, I got the answer...The thign that was confusing is that the series went up to M(1 +R)n-10 and there are in face 291 terms when u sum it up. But I got it eventually...

Ban the anti-semite troll's stormfront ramblings and put an end to this nonsense

Was the independent paper really hard or something? or was it just about non-sensical stuff (like 'write a job description' etc.) instead of like "describe ways of backing up data?"

WOW! did u come first in the state for 3 unit?

Just bringing the three up because its x^5/3 /(5/3) = 3x^(5/3)/5 then replace with a because thats the limit ur integrating with the next one i worked out the integration and then cross multiplied...

For the last one just integrate and find a, i got a = √5 .. Integrate[From 1 to a] (x(2/3) + x(-4/3) ) dx = x5/3 / (5/3) - x-1/3/(-1/3) = 3a5/3/5 - 3/a1/3 +(12/5) = (12/5) so 3a^5/3 * a^(1/3) = 15 3a2=15 so a = √5

The Smith's borrow $150 000 from the Bank at 9% pa. compounded monthly for 25 years. The Bank has a special deal - no repayments are required for the first nine months. (i) Show that the amount owing after 1 month is: 150 000 (1.0075) (ii) Show an expression for the amount owing after 10...

Umm I remember downloading a sheet from the resources section of this site, its under the heading "induction"...actually its quite good, it goes through virtually all of the types of questions you could be asked.

With questions 9 and 10...Just keep practising and leave plenty of time for them. Really you can finish a 2 unit exam (at least questions 1-8) in under 2 hours, leaving over an hour for questions 9 and 10, and some time for checking ur answers...Unfrotunately theres no easy way out for the tough...

Of course it is. In fact its EXTREMELY IMPORTANT especially in the second question

Is that where real slide rules come into the picture? I mean aernt they used for that sort of thing?

The double angle formulas and the 6 compound angle formula are NOT in the 2 unit course. The only trig in the 2 unit course is the basic trig (sohcahtoa), the reciprocals (cosec, sec, cot), the sine and cosine rule, and the pythagorian identities(i.e. sec2@ = 1 + tan2@ etc.). And also the only...

I thought of that as well and then I read someone who said that it perhaps the book was his mother's, and she just passed it down to him an dso snape wrote all over it...

She has stated that it would most likely be shorter than the order of the phoenix, and that would probably mean it should come out at around 2007.