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What was your study routine like?

Give them a call, maybe there's a letter currently being delivered to your place.

n = m/mw, which you already found to be as 0.02497 moles. C = n/v, where n is 0.02497 and v is 250ml/1000 to convert it to litres, and that'll get you the answer.

Determining whether a molecule is polar or not is pretty easy by knowing the overall dipole movement. Take a look at the picture below, the dipole vectors move towards the electronegative atom. If the overall dipole movement is 0, then it is non-polar. If the dipole vectors don't cancel each...

I wanted to see what this guys looks like.

Re: HSC Chemistry Marathon 2016 What's the question?

Woah, how'd you come across that?

The TPS option looks pretty easy this year.

Usually you just follow how the question has given the values, e.g. if they say 12.5ml used, then you would use 3 sig figs. It honestly doesn't matter as long as you have the correct working out and answer.

Yes

The campaign might be worth getting and refunding later on, but for multiplayer, it does look promising with the new guns and vehicles, so I'd say go for it.

Do past papers only when you have finished cramming your notes. No point in doing past papers if you haven't nailed the fundamentals first.

Re: ATAR Notes vs Bored of Studies Have you had a rough time on this forum?

Janek Drevikovsky. nuff said.

It's quite the interesting one. If there was Cl on one of the monomers reacting with another monomer that has the amine group, then HCl is formed. If there is an OH group, then water is formed. There are a few different pictures showing different things but I want to know, how did you come...

Yep. 100, 50, 25, 12.5, ... and so forth.

It's common sense really. Initially there is 100g of C-14, after one half life there would be half of 100g, which is 50g. So now you're left with 50g, and after a second half life you would have half of 50g, which is 25g.

If you were at my high school, they'll still make you do the test...

Too easy, band 7.

Not a fan of tackle ay?