Search results

Re: HSC 2013 2U Marathon <a href="http://www.codecogs.com/eqnedit.php?latex=\textup{Differentiate&space;}&space;\sin^{4}x\textup{&space;&plus;&space;}&space;\sin^{2}x.4x^9" target="_blank"><img...

how would i do that though? im sorry ahah, this is just really confusing me

ahh i see what your saying, thankyou!

Re: HSC 2013 2U Marathon Hahah thankyou! that was a really good question

Re: HSC 2013 2U Marathon is it 6/squaroot of 10 ? haha, im using the perpendicular distance formula

Re: HSC 2013 2U Marathon wouldnt the closest distance be between the line y=3x - 1 and y = x^2 + 3x + 5 is when their gradiesnts are exactly parrallel?

im just worried they wont award me full marks for thinking i looked at someone elses sheet etc.

Re: HSC 2013 2U Marathon is the answer 2?

Re: HSC 2013 2U Marathon I am baffled to how i'd even start this question,

Re: HSC 2013 2U Marathon haha try to relax, you'll do much better, stress ruins long term memory, and just makes your primary senses alert

Re: HSC 2013 2U Marathon i took a common factor of secx if your talking about the change from cos to the power of 4 to them two brackets, you use this rule <a href="http://www.codecogs.com/eqnedit.php?latex=(x^{2}-1)&space;=&space;(x&space;-&space;1)(x&plus;1)" target="_blank"><img...

its a 1 marker though, so im really curious if, that id have to expand all that

Re: HSC 2013 2U Marathon Haha, what do you mean? though the second last line does seem confusing

Re: HSC 2013 2U Marathon <a href="http://www.codecogs.com/eqnedit.php?latex=\frac{\sec&space;x&space;-&space;\sec&space;x&space;\&space;cos&space;^{4}x}{1&plus;\cos^{2}x}" target="_blank"><img...

http://www.boardofstudies.nsw.edu.au/hsc_exams/hsc2010exams/pdf_doc/2010-hsc-exam-mathematics-extension-1.pdf I dont really understand how to prove it?

Re: HSC 2013 2U Marathon the question didnt specify area, but just an "integral" if it asks to use this integral to find an area you would take absolute value

Re: HSC 2013 2U Marathon <a href="http://www.codecogs.com/eqnedit.php?latex=\ln^{2}x&space;-&space;3&space;=&space;2.\ln&space;x" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\ln^{2}x&space;-&space;3&space;=&space;2.\ln&space;x" title="\ln^{2}x - 3 = 2.\ln x" /></a> <a...

Re: HSC 2013 2U Marathon Yes, you got to get it a base of e, but im sure you got it, i have the full solution on the same page

Re: HSC 2013 2U Marathon <a href="http://www.codecogs.com/eqnedit.php?latex=a&space;=&space;1&space;\textup{&space;r&space;}&space;=&space;\sin^{2}x" target="_blank"><img src="http://latex.codecogs.com/gif.latex?a&space;=&space;1&space;\textup{&space;r&space;}&space;=&space;\sin^{2}x" title="a...

Re: HSC 2013 2U Marathon <a href="http://www.codecogs.com/eqnedit.php?latex=\textup{Let&space;}&space;t&space;=&space;1" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\textup{Let&space;}&space;t&space;=&space;1" title="\textup{Let } t = 1" /></a> <a...