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Search results

  1. A

    help = integration problem!

    nup i havnt got the correct answer but its liek a follow on question... <input id="gwProxy" type="hidden"><!--Session data--><input onclick="jsCall();" id="jsProxy" type="hidden">
  2. A

    help = integration problem!

    lol im confused... :S umm its 1/(3-x)^2 are u guys using that formula: integral of (ax+b)^n = [(ax+b)^n+1]/(n+1)a ?? <input id="gwProxy" type="hidden"><!--Session data--><input onclick="jsCall();" id="jsProxy" type="hidden">
  3. A

    help = integration problem!

    lol im confused... :S umm its 1/(3-x)^2 <input id="gwProxy" type="hidden"><!--Session data--><input onclick="jsCall();" id="jsProxy" type="hidden">
  4. A

    help = integration problem!

    ooo ok thanks heaps!! :D <input id="gwProxy" type="hidden"><!--Session data--><input onclick="jsCall();" id="jsProxy" type="hidden">
  5. A

    help = integration problem!

    hey guys ive gotta mental blank...:confused: how do u integrate: 1/(3-x)^2 thanks heaps for the help!! :) <input id="gwProxy" type="hidden"><!--Session data--><input onclick="jsCall();" id="jsProxy" type="hidden">
  6. A

    Study Discussion

    Re: Studying during hols hey haha goodluck for the half yearlies.. must suck dont even get a hol ><" hmm yeh i guess i could try those ideas out xD and lol 12hrs a day ..><" thanks! =)
  7. A

    Study Discussion

    Re: Studying during hols ahhk thanks im new here .. so didnt know
  8. A

    Study Discussion

    Studying during hols hey guys i was jus wondering about how much should u be studyin per day for each sub during these hols??
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