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  1. J

    neutralisation question help^-^

    can anyone give me a full answer, and explannation, please!! Thanks
  2. J

    neutralisation question help^-^

    Question: in the neutralisation, the enthalpy is lower for the products than it is for the reactants, identify the effect of this on the heat of the reaction. help please, thanks you so much, guys
  3. J

    find x^2+y^2

    sorry, i did something wrong!! (x+y)(x^2+xy+y^2)=19 (factorise x^3+y^3=19) should be (x+y)(x^2-xy+y^2)=19 therefore: x^2-xy+y^2 = 19 this lead to x^2 + y^2 = 19 + xy...................(1) because: x^2 + 2xy + y^2 =1 , this lead to x^2 + y^2 = 1 - 2xy...............(2) equation (1) -...
  4. J

    find x^2+y^2

    because: x^3+y^3=19 therefore : (x+y)(x^2+xy+y^2)=19 (factorise x^3+y^3=19) because x+y=1 (given) therefore: x^2+xy+y^2 = 19 this lead to x^2 + y^2 = 19 - xy...................(1) because: x^2 + 2xy + y^2 =1 , this lead to x^2 + y^2 = 1 - 2xy...............(2) equation (1) - equation...
  5. J

    help with polynomial, please

    Sorry guys, this was my first time posted in the wrong forum, forgive me ............:(:(
  7. J

    help with polynomial, please

    no,,,,,,, can u do it? please
  8. J

    help with polynomial, please

    Question: When a polynomial is divided by (2x+1)(x-3), the remainder is 3x-1. What is the remainder when the polynomial is divided by (2x+1)
  9. J

    Logarithms - Need Help!!!

    log10(1+y) - log10(1-y) = x log10[(1+Y)/(1-y)] = X 10^X = [(1+Y)/(1-y)] :lol:
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