Search results

Im not sure if i did this question correctly, could somebody check for me. Thanks. If u1 = 1 and un = root(2un-1) for n >= 2 a) Show that un < 2 for n >= 1. Step 1. If n = 1, u1 = 1 ***< 2 therefore true for n = 1. Step 2. Assuming true for n = k, uk = root(2uk-1) < 2 Step 3...

cool. thanks again riviet ;)

Ok theres a question, im not sure if what i did was right.. well i think it is..but anyway its best to check hehe. If you have an induction question such as the following: If u1 = 5, u2 = 11, and un = 4un-1 - 3un-2 for n >= 3, show that un = 2 + 3n Is it ok to do the following: 1...

Yeah im planning to do it in pencil on the adjacent page :D

Woops i wrote the question wrong, sorry. it was meant to be (ac – bd)2 I think you misunderstood me. What i was asking was if i could do it backwards (say on another piece of paper, or in pencil on another page) and then copy that "backward working" in reverse onto the HSC paper (with...

Is it ok to do this: E.g. Show (a2 – b2)(c2 – d2) <= (ac2 – bd2) Working backwards: (a2 – b2) (c2 – d2) <= (ac2 – bd2) a2c2 - a2d2 - b2c2 + b2d2 <= a2c2 – 2abcd + b2d2 - a2d2 - b2c2 <= - 2abcd a2d2 + b2c2 >= 2abcd a2d2 - 2abcd + b2c2 >= 0 (ad – bc)2 >= 0 Then what I write on my...

Oh sorry.. nuh i didnt really intend for someone to actualyl do it for me..i appreciate that.. just i guessed that people would have had to already have done it..so yeah just wondered if someone could check their answer.. Thanks for typing it up riviet..

I'm having trouble getting the answer i the back of the book.. If anyone has done this question, could they please check for me> It's Cambrdige Exercise 7.3 Q11b The answer says 10(root2 - 1) ms-1, but i get 5(2root2 - 3) ms-1... Yeah ive done the question twice..keep getting that...

nevermind me figured it out..thanks anyway

I have another question that i hope someone can help me out with, A particle of mass m is projected vertically upward under gravity in a medium in which the resistance is mk times the square of the pssed, where k is a positive constant. If its speed of projection is equal to the terminal...

oh god im so stupid.. forgot about partial fractions.. :|

Im having some trouble with the second question in the exericse 7.2 from cambridge. I can get the distance, but not the time (can't seem to be able to integrate the acceleration in terms of t...) 2. A particle is moving vertically downward in a medium which exerts a resistence to the...

i hope so

Im not worried bout the jigging of individual classess.. i dont think my teachers would do anything (well maybe my english teacher), its full day attendances that worries me..

How can the school not warn you that your in risk of not being able to sit the hsc. Sounds weird..

Ok well at the begining of the term, i stayed home mostly due to the fact that my school is just so distracting... i mean every single one of my classes is a waste of time (except maths), every lesson we dont do anything and i cant work individually due to the fact that everyone else isnt...

Im really worried now about my attendance.. Ive counted.. (approximated) that ive had 21 days off this term... maybe about 10-15 days last term, and maybe 6-8 days in terms 1 and 2 (although my report says 4) So adding it up gives maximum of 44 and minimum of 37 days. I heard that 85% is the...

You werent very clear in what you wanted, but this might be useful. Select Case Label1.Caption Case "0" Form1.Show Case "1" Form2.Show Else Form5.Show End Select Repost describing what you require in more detail.

uh huh... anyway.. so vafa, i still dont get the point you were making with all the stuff you said... you said for the acc. if you take x = 6, then acc < 0, but if you take x = - 6, acc > 0. well i took x = 6, but from the question it states the displacement is 6m from the origin. This does...

For this question: A body is vibrating in simple harmonic motion, the period being 12 seconds and the amplitude 10 cm. What is the velocity and acceleration of the body when the displacement is 6 cm. x'2 = n2(a2 - x2 12=2pi/n n = pi/6 a = 10 so when x = 6, x'2 = pi2/36(100 - 36)...