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Yes platinum is still used. In fact, its often used when something is getting bubbled into solution (Cl2) as it doesnt take part in the reaction. Chemically inert means it will not take part in the reaction. The electrolyte contains ions and these will just build up on the Pt electrode

Wouldnt it become less green as the Fe2+ is more easily reduced.??

James youre correct for the 33e) (iii) For the 33e(ii) the copper solution would go darker as platinum is chemically inert (i think it is anyway) and thus it would receive the electrons from the copper. Ions from the copper will go into solution making the solution a darker blue (the Cu2+...

30% is testable. And i am not even kidding.

I dont think that is the case as the marks that your school submit to the board are well before the exams and thus you get a rank which correlates to the rank that you for you assesment mark. The sentence above makes no sense but who cares.

They ones that were 3rd and 4th probably did bad in their hsc exams

If you get the large bottles. I think theyre like 475mls then youre only allowed to have one. I have done three of those in one night. I am not scared of the caffeine but more the sugar.

My school uses Fortiguard. Its so silly but if you log in as a teacher then you can literally view anything you want... Even bad things.

if this is one of the laptops then you can put a new Hard drive in then you install safari or FF then you can configure it to use your home internet.

You cant even do A) There isnt an option to the correct answer.

I have no idea what you do about the equivalence point thing...

Firstly you have to write a balanced equation or else it will muck up your calculations. So i think you have a total of 0.1 molar NaOH (Were starting this at school now so i am not 100% sure) and you have a volume so you have 3 out of 4 parts. You can now solve for 'n' (i think) So is the...

ML, How come you didnt come 1st for MX2? LoL:) I dont know whether to laugh or to cry, But seriously, 20 papers arent going to cut it.

So its not actually in the HSC?...

1- Set the telescope to 10x objective 2- Place the grid under the telescope 3- Estimate the field of view. 4- Turn/Change to 40x objective. 5- Divide your FOV by 4 as you have changed your objective by a multiple of 4. That is, if your FOV was 1640um then the FOV should be 410. (1600 or 1640...

Does anyone have any of the from the last couple of years. It would be greatly appriciated or if someone could show me where to download them from.

Well done Exploitable. I will probably have to get my hands on a copy of the SuccessOne Physics. What year was this question from.

Is there even enough data for B? Dont you need to know 4 knowns values?. I cant find time nor verticle/horizonaltal velocity from the available data. Its proably just me.

Either youre a fucking knobjob or youre fucking clueless. I think you need to re-read my post moron.

Okay now that i am on a computer i will put to you what i wanted to say. Because you equate f=mg then g is the value of local gravity, ie 9.8ms^-2 but the force of attraction where large or small is used to find the value in Nkg^-1. But for smaller masses the value m2 can be left out because...