u use the chain rule
consider y=25(1 - t/60)2
let u = 1 - t/60
then y=25u2
you're trying to find dy/dt right?
dy/dt=(dy/du).(du/dt)
now y=25u2
so dy/du=50u
or = 50(1-t/60) as u = 1 - t/60
and u = 1 - t/60
so du/dt = -1/60 (this is because t/60 is same as (1/60) x...
initially the kid's weight is 274N (from W=mg), i.e. 294=GMm/r2 where M=mass of earth, m=kids mass.
for (b) the mass of the planet triples so the new weght, W = G3Mm/2
we know from before that GMm/r2 = 294, hence the new weight = 3x294=882
the initial weight of the kid is 30x9.8=294N
using newtons formula F=GMm/r2
initially this equalls 294N
(a) if 'r' is tripled, sub that in to the formula and u'll get 1/9 of the original, that is 32.67N.
(b) same concept but sub in M as 3M, so u'll get 882N
ok here's how i did it;
for A at start not at end
there are 7 spaces to be filled
for the 1st space it has to be 1 of the A's so 3/7
the last space can be filled by any of the remaining letters except the A's so 4/6
so total probability for A at start not at end is 3/7.4/6=2/7
you...