Search results

I wish i could do ESL... It's a shame i was born here...

Generally a double root, means a turning point and a triple root a horizontal point of inflexion. You can demonstrate these results as such: If a is a double root of f(x) then, f(x) = (x - a)2g(x) f'(x) = (x - a)[2g(x) + g'(x)(x-a)] When f(x) = 0, x = a When f'(x) = 0, x = a Or...

MUCH longer...

yeah man i hate english so much....makes me upset and frustrated... all the texts are bullshit boring crap... only text i thought was ALRIGHT was educating rita...rest were stupid..

hahaha.. yeah that is better...Didn't even think of that! we havent really started much of polynomials. I was using 3 unit stuff.. but thats way seems so much easier... look how short it is compared to mine. Well... at least got the right answer!

This looks like its gonna take ages to write. Let alpha = A beta = B gamma = Y delta = D x^4 + 0x^3 + ax^2 + bx + 36 = 0 A = B = 2 (equation has a double root) A + B + Y + D = 0 4 + Y + D = 0 Y + D = -4 ---------------------------- AB + AY + AD + BY + BD + YD = a 4 + 2Y +...

Hey i just did that question! And yeah i can do it.. I want someone else to do it though so i can check my answers (even though im pretty sure they're right). And to the poster, if you dont get it, id be glad to post up my solution.

i suck at english... my marks are (these are from last term though) English Std: 50% 49th 2u maths: 100% 1st 3u maths: 100% 1st 4u maths: 87% 3rd English Again: 75% (dunno bout rank) SDD: 91% 1st

To buy electronic equipment such as wire, light globes or ect. you can visit dick smith (try to go to a bigger one, such as a powerhouse, as i think some of them dont sell electronics equipment). You could also try Jaycar. And for prices, wire is VERY cheap, and globes i think are 50c or...

You could be right..and according to the answer you are. Would you like to explain what you mean by it being clockwise because of the right hand push rule. The reason why im opposing the answer is because well for one i worked it out to be anticlockwise (thats obvious) and in the surfing physics...

What is the direction, clockwise or anticlockwise, of the induced current in the loop of wire in the following situation: (Please see attached diagram. See Fig. A and Fig. B) I say anticlockwise, but the answer says clockwise. The following is my reasoning. As the current increases, so...

oh ok cool..thats what i was looking for..thanks!

no no ah....................... man i know all that!!! what i want to see demonstrated is the writing of the roots without the square root symbols. Like equating a + ib = Root(something + i*something) and then you square both sides, ect.

mehh... thats not the part i was confused about... seems people cant be bothered to help hehe.. i dont blame yuo though...erm what i was stuffed about is the square rooty things..erm.. i had z = +/- root(1 +/- i root2) and yeah thats what i was stuck on..

Theres a question im doing.. well i think ive done it but im not sure if my steps are right.. i forgot everything practically bout complex numbers.. and so can somebody do this question with full working out please: Find z in z4 - 2z2 + 9 = 0.

That was obvious.. How stupid of me..

I just need verification. The question asks: Show that the miniumum value of y = x log x is -1/e. dy/dx = log x + x * 1/x = log x + 1 When dy/dx = 0 log x = -1 elog x = e-1 x = 1/e (no minus sign) d2y/dx2 = 1/x So x has to be positive for a turning point to be a minimum (as...

Wow god we have two classes with each about maybe 15-20.. thinking more 20ish. And its cool though cuz im third!! (for now that is... half yearly comming up soon). Actually i think theres about 50 something doing it all together.. Just a "possible" memory... so it might be bout 25 in each class...

I say wrong, because its not possible to find that series' limiting sum using the formula S = a / (1-r).

Find the limiting sum of the series: 20 + 15 + 12 + ... Considering the series, it is not geometric so how is it possible to find the limiting sum? By using the common ratio (which this question does not have) between term 2 and term 1, r = 3/4, you can calculate the limiting sum to be 80...