As x-> inf, y approaches inf as e^x is far bigger than x in e^x/x so numerator overpowers it significantly
As x-> -inf, e^x approaches 0, hence y approaches 0 from the bottom
I would have to say 88 - 89 currently (somewhere in the ballpark), which is definitely not indicative of his final atar as a banger externals would carry to 90+. Study hard!
Because both are symmetrical. (1+x)^n = nCr * 1^r * x^n-r = nCr * 1^n-r * x^r
If you stick with one, u have to use the same one i.e. can't use one this way and the other that way