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If its not graphics or driver problem then.. http://www.memtest86.com/ Check if any of your RAM/RAM slots are screwed.

I sleep at like 12pm~1am and wake from 8am~9am, depending on which days I have free periods early. But average 8 hours or so. Woot. xD

Okay I got it. I think. C = (500/v)(150 + v2/80) = 75000v-1 + 25v/4 C' = -75000v-2 + 25/4 St. Points at C' = 0 75000v-2 = 25/4 300000v-2 = 25 1/v2 = 25/300000 v2 = 300000/25 v = 110, -110 v >= 0 Therefore 110km/h

Holy crap. I forgot all about Maximum and minimum. I have no idea how to do this anymore. Damnit. Whew, glad I found this thread. =D Do you have the answer to the question? Is it 77km/h? I have a weird feeling I'm way off.. Nevermind. I'm horribly wrong.

The "night before" rush? xD

Is boredom a reason?

A UAI of 70 shouldnt be hard to achieve. I dont think the subject you're doing scale particularly well but as long as you get good marks in your assessments relative to those in your grade doing the same subject, then you'll easily make 70.

I wish I had a scanner. Typing this shit up takes forever.

0∫4√3 dt / (16 + t2)3/2 ----------------------- Let.. t = 4 tan Ө dt = 4 sec2Ө dӨ when t = 0, Ө = 0 when t = 4√3, Ө = pi/3 ----------------------- Therefore 0∫4√3 dt / (16 + t2)3/2 = 0∫pi/3 (4 sec2Ө) dӨ / (16 + 16 tan2Ө)3/2 = 0∫pi/3 (4 sec2Ө) dӨ / (4√(1 + tan2Ө))3...

I have a feeling I'm way off. Is it: Root(3)/32?

Whoo. This one is messy. xD

Tie your hands to a table or something. And get your brother/sister to pull your legs for a few hours a day. Bound to get some results.

Hahaha. We need to take all the love advice on this whole BoS forum and make a FAQ for boy/girlfriend problems. "Harden Up" would be the answer to half of them. xD

I think thats right. Assuming i didnt miss something while typing it up. In the end I got 25pi/4 Whats the answer meant to be?

0∫5 (25 - x2)1/2 dx ----------------------- Let.. x = 5 sin u dx = 5 cos u du when x = 0, u = 0 when x = 5, u = pi/2 ----------------------- Therefore 0∫5 (25 - x2)1/2 dx = 0∫pi/2 (25 - 25 sin2u)1/2 (5 cos u) du = 0∫pi/2 root(25 - 25 sin2u) (5 cos u) du =...

Yes but. Say h was lower. Therefore max height is lowered making the parabola flatter. Which means that the horizontal component will have to increase to reach the bird? Okay I'mma head to sleep. This makes no sense at all right now.

Haha. Yeah. Bored Aussie was good. Didnt BA close down last year? And it came back. During the "down" time everyone just moved to another Battle.net server, Aus1. Its mainly a starcraft based Aussie Battle.net server though. Bleh. I want Starcraft II.

Mine are all in the 4 days of next week. Woot! Fail time! English and Conics is gonna screw me over.

You must love your subjects. I mean. Very very muchly. Enough to have babies with them. 10 Units is all I'm doing.

I still dont see it. Or maybe I've got something on my mind and Its wrong. Height of the pole is variable, right? Wouldnt the horizontal component of the rock vary as it was lower or higher? Maybe its cause I'm sleepy. I dunno. But it just doesnt make sense at the moment.