I got -1 and 3, you can check if you got it right by substituting these n vales in the original equation and solve it to check if the roots are consecutive
Let roots be a and a+1
Addition of roots = 2a + 1 = 5(n-1)/2
Product of roots = a(a+1) = 6
Solve equation for the 2nd equation. The substitute both values of a into the first one to find n. There are two n values
Yup, you chose to have them, you chose raise them. I.e you volunteered to raise them.
hence work in raising them should not involve money or even be seen as being worthy of some cash
Markers are smart enough to follow someone's reasoning regardless on how they express it (assuming the reasoning makes sense). If not then what the fuck they should be
Spiralflex is pointing out that the question didn't give the bounds and that you found the bounds with the given answer and hence was able to post the solution OR you've done it before