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The cram is real.

Which paper is this?

Well this forum is Bored of studies =). Did something draining in particular happen at school today or was it just a bit busier than usual? I remember sleeping in classes a lot last year (though mainly it was because I was watching an anime series =P).

I can predict that there will be maths and that it will probably be a bit easier than last year.

I think faisalabdul16 would agree with me when I say: MIF is good for you.

Right, cool. Notes from marking centre: "Of the few candidates who attempted this part, most gave unnecessarily lengthy arguments involving similar or congruent triangles. A few obtained the answer quickly by recognising the intercept property of lines through the mid-points of two sides...

What year is this exam?

What textbook?

Either drop the one that you're least passionate about or wait till first assessment and drop the worst one.

In regards to your other question, midpoint theorem is probably the fastest way, can't really think of any others. (Well, I could but the work required would probably be too tedious for the 1 mark)

That is a legit theorem (I remember learning it in 2 unit maths). If you have the Year 12 Pender book, you can find that theorem in there as well (page 332, of my copy at least).

Will the solutions be released soon?

It means prove by induction angle sum of an n sided polygon is 180(n-2)^{\circ}$ or, if you prefer radians, $ \pi (n-2)

Just in case, they have the nuclear football on hand as well.

rofl; good to see your English skills being used productively ^__^.

It is in the book. Chapter 6.

What were your thoughts on this year's Latin exam?

Well it does say on the front of the paper to show relevant reasoning and calculations :spin:

What. We haven't even sat the MX2 exam yet so he has to be talking about last year's haha. Plus,

Well Carrot, don't answer this if it violates your code, but which school won the 'massive selective schools battle'? I think mreditor's also interested to know the outcome haha.