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lemme guess, based on the last 2 years of BOS trials, I'm guessing the last question will be complex numbers/polynomials lol

Probably a hyperbola and an ellipse mixed with reflection property, oh god the tears. It kind of sucks that there are limited questions on this property.

Yeah, all strings must be taut (i.e. T>0). For (d), the tensions T1 and T2 must be equal for P to be fixed.

Re: MX2 Integration Marathon , nothing too hard, just tedious. Next:

You realise, most of the past papers are copy and pasted from CSSA/Sydney Grammar/James Ruse/HSC papers. Kind of counterproductive when you see the same question appear 5 times lol

I know how you feel, you reach the point where you need a new flavour, but you don't know how or where to find it. I am currently in a similar situation where I have no idea how I can further my understanding and application of concepts. I want to get better and reach the elite tier and I feel...

Re: HSC 2014 4U Marathon - Advanced Level It's not, but my teacher is a real big fan of it lol

Re: HSC 2014 4U Marathon - Advanced Level Seeing that there is an oblique rotation question, I may as well post the question we had in 3rd 4u task :)

Well I'd be down :)

Well, last year I basically did not study for 2u since I knew I'd be picking up 4u and it wouldn't count. But yeah, I believe that if your ext 1 is good, then naturally your understanding of 2u concepts should be a piece of cake.

Then again, there are multiple ways of proving that result lol

Anyone have SGS 2013 MX2 trial by any chance. Considering they had one of the most competitive and best performing cohorts, I want to have a go at it :)

wut

My teacher told me to overkill each short answer question because of this reason. Obviously answering the question properly in term of the directive but going more in depth. Also, try and fill all the lines up because psychologically it gives them a sense of completion and could be the...

Knox grammar maths teachers are lazy as fuck lol

Re: HSC 2014 4U Marathon - Advanced Level Yeah, I know it's indeterminate. It was just a hunch lol.

Re: HSC 2014 4U Marathon - Advanced Level Is the definition even needed? I ended up getting 1 just by inspection because [tan(pi/2)]^0 =1

For part (c), you have to find the condition for the circular motion to exist. We set T2 > 0 and solve because T1 is always > 0 since r, w, g and m > 0 and also since 0 < θ < 90 (i.e. acute angle) -> implying sinθ and cosθ > 0. As for (d), think about when P is fixed (Hint: Consider the tensions...

They made you find h and r in part (ii) and your final expression had no h's or r's but instead l's. From that, it is obvious that we had to eliminate them. Coincidentally, h, r and l are linked via Pythagoras. After using the pythagoras theorem, we find that the expression we obtain after...

Re: MX2 Integration Marathon so the answer should be e^4.6 which is 99.95 (2dp)