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from memory it was about 52-53/70 in 2012 and last year i remember someone saying 48/70 was the bottom e4

Auxiliary angle method involves taking an expression in the form asinx + bcosx and changing it into a single function. This is the method that involves dividing to get tana in terms of a constant. in this case the question was cosy - \sqrt{3}siny \\ \text{We want it in the form} \\ Rcos(y+a)...

rote learning is very achievable for HSC science because the syllabus is extremely succinct. I agree with RoT about state rankers understanding the content of course though. In order to truly nail those 6/7/8 markers (which can ONLY come from syllabus dot points that require you to discuss...

pretty much this! it's an exhilarating course, but not for the lighthearted :) i wouldn't suggest it if you have over 12 units already in prelim

i would have gone with +-pi/2 for the same reasoning, but i don't like questioning terry lee...

answers are wrong, should be 200/3 (66.66)

yeah you're right spiral, inverse functions isn't in 2U.

pretty impressive find (Y)

I thought it was pretty typical for a Ruse paper honestly... wasnt easier than 2012 or 2011. 14a I havent seen exactly, but a similar q was in the BOS 2013 MX1 (I know because I did that timed 2 days ago). Id be interested to see the victorian paper and their solutions :P

Yeah i already understood this lol i'm just saying that that's not at all how i interpreted that wording. Like i interpreted that as we know one dice is a 1, therefore there is a 1 in 6 chance of the other dice also being a 1. Ah i now see why 9 isn't A, i assumed that closing the triangle...

9 is A.

See i completely disagree with this, if it says you KNOW you have at least one James Ruse student, it means the probability of having at least 1 James Ruse student is 1. So you're dividing by 1. It implies that the first case has already happened, otherwise it wouldn't even need to bother saying...

well change D to E, and make the bisecting line intersect at D. It clearly doesn't bisect line BE

i didn't get the fact that it wasn't just (n-1)/(N-1)...

no it doesn't, that's exactly what my diagram showed...

it's in my previous post

i drew a diagram to show what i mean by constructing BD

D isn't there at all. i mean construct line BD so that D lies on AC, but D is close to the point A.

definitely not. pretty easy to see why, just draw an exaggerated case. place point D up near A and look at line BD. the section the subtends angle gamma is much much much shorter than the section that subtends angle alpha.

My multiple choice was 1- A 2- A 3- B 4- D 5- B 6- ? 7- C 8- D 9- A 10- ?