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i finished a timed attempt about an hour ago and i'd like to mark it :/

does anybody have a copy of solutions to the JRAH 2013 MX1 Trial? bloody tough paper for an MX1, need a copy of them soln's much appreciated in advance :D

lol this is exactly what i said at the start

y = x^{x} \\ log_{x}{y} = x \\ \frac{lny}{lnx} = x \\ lny = xlnx \\ y = e^{xlnx} \\ \frac{dy}{dx} = e^{xlnx}(1+lnx) \\ = x^{x}(1+lnx) Hope this helps.

because otherwise it could be an arithmetic series, and k would be (80+5)/2

Re: HSC 2014 4U Marathon - Advanced Level I'm just a little confused, by using the sine rule with alpha as angle ADP shouldn't we get sin(theta) = xsin(alpha)/2? unless that's meant to be angle DAP?

if you got 96 with 59/70, how would 90 be 56/70?

last year i got about 56-57 and i got 47/50. the year before it was 51 from memory. lol it's definitely not 56+

i think somewhere between 50 & 52 out of 70.

Well it passes through the points (0,6) and (2,0). Sub them in and solve for V (theta is 0 because horizontal projection).

I wouldn't call it spoon feeding, it's just giving a solution - because that's exactly what I'm looking for when I post a question on here.

I usually substitute it in at the start, but if the question says "...The angle of elevation now changes..." or "...The starting velocity now changes..." in a later part, you'd be better off to have done it with V & alpha. I never do it that way simply because i feel like it's just a memorized...

Dammit someone always beats me by a couple of minutes while I'm typing it up with LaTeX.

Leading on from a) \frac{2t}{1-t^{2}} = 1 \\ \text{Now, solve for t} \\ 2t = 1-t^{2} \\ t^2 + 2t - 1 = 0 \\ t = \frac{-2 \pm \sqrt{4+4}}{2} \\ t = - 1 - \sqrt{2} \\ \text{The other root represents the other value of t for which } \frac{2t}{1-t^{2}} = 1 \\ \text{That is, } \tan{22.5} =...

I am currently first by a lot, there is very little chance that i won't be by the end of trials. I'm more concerned with the externals, but yeah i guess i hadn't thought about how much it would vary from year to year. I'll just make 96 my minimum goal then carrotsticks :P

Hey guys, im aiming for a state rank in MX1 this year, and I was wondering if anybody knows what raw score on the external usually gets someone a state rank (and dont just say 100%, I mean the lowest raw mark)? I go to a selective high, ranked top 30, my course average is nearly 98% and second...

It's Eddie Woo! :O You're legend, saved me many a time through my HSC last year! Keep up the great work, I know plenty of my friends have used your videos heaps and they've been a great help.

Re: MX2 Integration Marathon = \frac{3}{28}(x-2)^{\frac{4}{3}}(4x-1) + C

You also can't square root -1, but we still have i don't we? :S

It's something to do with the abs value that we impose when we integrate. If you leave it as: C= \frac{ln(-5)}{2} Then you get the same solution as the textbook.