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Wow people derailing these days ------------------------------------------------------- Next wk the provisional marks for first year maths comes out is that right?

Re: HSC 2014 2U Marathon I think it's meant to be 342390 (you didn't divide by 3)

Yeah when you work out the roots of z^6-1 = 0 you pretty much get 1, (alpha), (alpha)^2 ,(alpha)^3....(alpha)^5 as the roots where alpha is a complex root with the smallest positive argument use S.O.R of the polynomial which is 1+(alpha)+(alpha)^2 + (alpha)^3....(alpha)^5 =-0/1 = 0

for 3 I'd use sum of the roots of the polynomial

For 2a \\ \\ $since w is a root of$ \ z^3-1 =0 \ \ then \ \ w^3 - 1 = 0 \Rightarrow \ \ w^3 = 1 \\ \\ \frac{a+bw+cw^2} {c + aw + bw^2} = \\ \\ w^2(\frac{a+bw+cw^2}{aw^3+bw^4+cw^2}) = \\ \\ w^2(\frac{a+bw+cw^2}{a+bw+cw^2}) = w^2

Have a good sleep, eat well before the exam :) And just try and stay calm (I know it's easier said than done, but it's the best way to think clearly)

woah you're back!!!!

Re: HSC 2014 4U Marathon Yeah sorry that's not right at all I'll let P be point (Xo,Yo) $Tangent of P is$ \ \ y - y_0 = x_0(x-x_0) \\ $Sub x = 0 and B is point (0,y_0-(x_0)^2))$ \\ \therefore\ AB = 1-(y_0-(x_0)^2) \\ \\ $Note that$ \ \ y_0 = \frac{(x_0)^2+1}{2} \Rightarrow (x_0)^2 = 2y_0...

Re: HSC 2014 4U Marathon After fudging the algebra you get \\ y = \frac{x^2+1}{2} Then you realised that A is actually the focus of the parabola and B lies on the directrix, so therefore AB = PA from the focus directrix definition of the parabola. There fore the angles are equal as they are...

got dem HD? Almost there bro hang on. yeah fk off hahaha

when will the results come out?

NOOOOOO WHY DID NOT THINK OF L'HOPITAL!!!!! I WILL NEVER FORGET THIS NEXT TIME Ahh well thanks anyways

damn i wonder who got ln(c)

BUMP1!!

Chem1011 - content was nice, , notes were nice, steve colban was awesome with a decent sense of humour and his notes are well structured the best part was that i got a cute lab demonstrator, ended up taking a selfie with her YEAHHH

you didn't do jack shit m8 Anyways my quick review ENGG1811 (6-7/10) - Personally i'm bad at programming, the first half of the course is a bit of a bludge as it involves stuff with excel, but then the other contents like VBA and MAtlab are pretty hard, and you could get screwed if you don't...

lel the complex roots are purely imaginary, so they're simply in the form bi ,-bi (b is real) $let the roots be$ \ \alpha \ bi, \ -bi \\ $using Product of roots you get$ \ \alpha(\beta)^2 = \frac{-10}{3} \\ $us sum of roots 2 at a time to get$ \ b^2 = 5 \\ \\ $sub that in previous equation...

Re: MX2 Integration Marathon What da shiet is dis Anyway I'm guess it's like e^{e^{e^{e^x}} and ln(ln(ln(ln(x))))

Hey Ya I just had my final maths exam today, and some questions rekt me hard lol, and ODE (ordinary differential equation) question and a weird limit one $Suppose that y satisfies the initial value problem$ \\ \frac{dy}{dx} + y^2 = cos(x) \ \ with \ \ y(0) = 0 \\ $find the first non-zero...

just want it to ENDDDD