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Re: HSC 2014 4U Marathon \\ i) \ (1+ki)(k+i) = k +i +ki - k \\ = 0 + i(k+1) \\ ii) \therefore arg(1+ki)(k+i) = arg[(i)(k+1)] \\ \therefore arg(1+ki)+ arg (k+i) = \pm \frac{\pi}{2} \\ tan^{-1}(k)+ tan^{-1}(\frac{1}{k}) = \pm \frac{\pi}{2} \\ \therefore tan^{-1}x + tan^{1}\frac {1}{x} =...

yes I'm waiting to see the SR of yours in BIO ;) damn I"m actually getting a bit nervous now don't you?

Re: HSC 2014 4U Marathon Wouldn't it be better to expand (1+i\sqrt{3})(1-i) since that gives (something) cis pi/12 rather than cis 7pi/12

Re: HSC 2014 4U Marathon I think oblivious is only asking about the topic graphing ( not combined with conics )

Re: HSC 2014 4U Marathon lol I dunno if 2014 guys learn binomial at this stage . but anyways \sin(n\theta) = \sum_{k=1}^{n/2} \binom{n}{2k-1} (-1)^(k-1)\sin^{2k-1}\theta\cos^{n-(2k-1)}\theta $. I meant (-1)^(k-1) I'm just learning latex

According to whom?

Keen to see my maths and chem, :) But not so much on English

Kings always make you do extra stuff like that (in this case you have to realise that cos(4pi/5) = -cos(pi/5)

For part 2 It's using double angle formulas so Cos 4pi/5 = 2(cos 2pi/5)^2 - 1 Now let x = cos 2pi/5 Therefore you would get x + 2x^2 - 1 = -1/2 (Using part 1) Rearrange that to get 4x^2 + 2x - 1 = 0 We know that one of the solution is x = cos 2pi/5 (cos 72) Using the quadratic formula x...

For Q 2 After marking the points in the diagram You rearrange the equation and you get => z1-z4 = z2-z3 Therefore the vectors AD = BC Rearranging again you get z1-z2 = z4-z3 There fore AB = CD Since the opposite sides of the quadrilateral are equal, it's a parallelogram For the 2nd...

Re: HSC 2013 4U Marathon doesn't need polys :) Just complex numbers and algebra

it's actually f'(1) = 0, yeah it's not really clear lol

you get dem girls all day every day

I struggle with permutation and combination. Nuff said. (2013 only had 3 marks on that topic and they're the easy ones CHEERING) it's the only topic where I somehow can't really apply the basic concepts (is it just me??) But IMO projectiles is the hardest topic (though I didn't struggle as bad...

Re: Does anyone here play chess? Not many girls enjoys the competitions in chess, I wish there were more girls playing ;)

I started playing piano at probably around 7-8. At first it seemed "easy" when I started learning the scales and pieces cause I just somehow got into the rhythm. It sort of motivated me to practice lol (not too much but like 30-40 minutes a day) Wouldn't say I hate it, but when I started AMEB...

lol I what I've heard of students getting raw marks of high 80s last year and that's still a state rank

Amen to that :)

Ahhh I initially had this feeling, all I cared was getting doing well. I wasn't very social back then. When I started high school at some random private school, I met many people with various academic skills (some were talented, others are just average) and I got along with them really well...

Baby you're a firework!!!!!!!!