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If Q has the co-ordinates (-4ap, a(3-2p²)) then x= -4ap and y = a(3-2p²) p = -x/4a so y=a(3 - 2x²/16a²) y = 3a - x²/8a x² = -8a(y - 3a) Which is in the form (x - h)² = -4a(y - k)² where the...

I'm not that good with my conic properties but if you have a hyperbola like this intersecting a circle then would symmetry dictate that t₃ = -t₁ and t₄ = -t₂ ? If that's the case you could use the product of roots to quickly find that...

[And then I discover that you want the radius, rather than the fact that it is a circle. It would pay to read the question it seems... le sigh] A slightly different method which seems to do it: The gradient of VT: m_VT= (b²t₁t₂ -...

I got mine earlier today, wentworth park I think.

I am yet to learn those solubility rules... I should probably get onto it. Is there a definitive list of which solubility rules/flame tests/flow charts we need to memorise or is it up in the air a bit?

You need to be pretty well versed in the 2U syllubus. It contains the foundation techniques that you need for the 3U and 4U work. You will probably find that a lot of the 2 unit stuff becomes second nature given how much you will use the basic techniques but I wouldn't bypass 2U work all...

Xayma's post from the Notation sticky thread is a pretty good reference point for notation in the math forums. [unfortunately it doesn't work in most other places, e.g. physics]

You use an ampersand, followed by Delta, followed by a semicolon. &_Delta_; = Δ (but with the underscores deleted) Using a lower case d gives you a lower case delta. It works for most of the greek characters: Α α Β β Γ γ Δ δ etc...

I get a somewhat similar answer for B: 1 - [ P(2rainy) + P(1rainy)] = 1 - [ ( ¹⁸C₂ .¹²C₃ / ³⁰C₅) + ( ¹⁸C₁ . ¹²C₄ / ³⁰C₅)] = 1 - [2365/7919] = 0.7012...

It's handy to keep the general form at the back of your mind for integrals: cos²(nx) = 1/2[1 + cos(2nx)] sin²(nx) = 1/2[1 - cos(2nx)]

I've been able to finish most of the trial papers that i've attemped in a little over an hour (averaging at just under 10 mins per question). I think that this is a little too fast so I'm going to try and slow down to cut down on careless errors/silly mistakes. Run through past papers and find...

As far as physical 'extra dimensions' go, I'm skeptical, but as far as fancy mathematical constructs go I think that they can work even though the conceptual premise behind them might be incorrect. While there might not actually be (10/11/26 etc.) dimensions, it's still possible that...

This is a fact that I have spent quite some time trying to deny :p. Physics was the reason I got interested in maths in the first place because I had that drive to understand those abstract symbols and what they imply for the world around us. It's actually the interpretation of the...

The way in which you title your threads makes me stressed. (And yes, I have experienced a similar guilty. I havn't been doing nearly as much work as I should have but in this case it's largely not my fault. I've been pretty sick for the past week such that on a couple of days it's been an...

Nice application, it's always a good exercise to try and find more ways of doing a question. Also, your enthusiasm is understood, it's quite a cool method :p. One trick I've noticed you using which I never knew you could use is the following: If p/q = ∞ , then q=0 Is that a normal...

Another go :p : Let the angles be a, b and c at the points A, B and C which are 10, 20 and 30 metres from the foot of the post F, respectively. Name the top of the post H. Since a+b+c=90 --> cos(a + b + c) = 0 cos(a+b)cosc - sin(a+b)sinc = 0 cosa.cosb.cosc -sina.sinb.cosc -...

haha, well at least my mind is put at ease. I thought that being flu-ridden wouldn't stop me attacking a maths question, I thought wrong :p.

How not to do the question: sina = h/AH --> AH= h/sina (1) AH/sinb = BH/sin(90-a) --> AH = (sinb.BH)/cosa (2) Equating (1) and (2) h = tana.sinb.BH (3) considering the Δ BHF, cosb= 20/BH hence BH= 20/cosb (4) Subing (4) into (3) h = 20.tana.tanb , but tana = h/10...

I suspect that I would have prefered the old syllubus to the new one, but if it's just the difference between a several more basic equations then it's much of a muchness really. If anything gets to me it's the questions in the vein of 'assess the affect of the transistor on society'. By the way...

I resent the fact that it has become necesary (more or less) to do prep courses for the UMAT but I did the medentry course: http://www.medentry.com.au/news.asp Which consists of: - Two Day Workshop - 10 Full Length UMAT Practice Exams - Guides for all the sections - Extra...