Re: HSC 2016 4U Marathon
Given P ( a cos theta , b sin theta ) and Q ( a cos phi , b sin phi ) lie on the ellipse x^2/a^2 + y^2/b^2 = 1
IF PQ subtends a right angle at (a,0) show that ( tan theta/2 ) X ( tan phi/2 ) = -b^2/a^2
How does b (sin theta - sin phi ) / a (cos theta - cos phi) = b/a...